The crate moves at constant velocity, this means that its acceleration is zero, so the net force acting on the crate is zero (Newton's second law).
There are only two forces acting on the crate: the force F applied by the worker and the frictional force, acting in the opposite direction:

, where

is the coefficient of friction and

is the mass of the crate. Since the net force should be equal to zero, the two forces must have same magnitude, so we have:

And so, this is the force that the worker must apply to the crate.
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Answer:
a) Kinetic energies
K₁ = 1.2 J
K₂ = 7.5 J
b) The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s , K₂ = 7.5 J
c) K₂ -K₁ = 6.3 J
Explanation:
The kinetic energy (K) is that due to the movement of a body and is calculated as follows:
K = (1/2) m*v² (J)
Where :
m : the mass of the body ( kg)
v is the speed of the body (m/s)
Data
m₁ = m₂ = 0.006 Kg
v₁ = 20 m/s
v₂ = 50 m/s
a)Calculation of the kinetic energy
K₁ = (1/2) (m₁)*(v₁)²
K₁ = (1/2) (0.006)*(20)²
K₁ = 1.2 J
K₂= (1/2) (m₂)*(v₂)²
K₂ = (1/2) (0.006)*(50)²
K₂ = 7.5 J
b) K₂ ˃ K₁
The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s, K₂ = 7.5 J
c) Difference of their kinetic energies (K₂ -K₁)
K₂ -K₁ = 7.5 J - 1.2 J = 6,3 J