Answer:
A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.
1. 40-0=40
3. 40/5=8
8 ml/s
you find the range of acceleration(step one)
divide by the time(step two)
Answer: 12
Explanation:
Let’s take for instance the case of a wave with a frequency of 400 Hz going through a material at a speed of .5 m/s. The wavelength result is 12 m. Wave velocity (m/s) = Frequency (Hz) x Wavelength (m)
The answer is position 3, because it is at its lowest point.
Potential Energy is “stored energy.” It is energy that is ready to be converted or released as another type of energy. We most often think of potential energy as gravitational potential energy. When objects are higher up, they are ready to fall back down. When you stretch an object and it has a tendency to return to its original shape, it is said to have elastic potential energy. Chemical potential energy is the stored energy in a substance’s chemical structure that can be released in a chemical reaction or as heat.
Answer:
![|\vec r|=339.82\ m](https://tex.z-dn.net/?f=%7C%5Cvec%20r%7C%3D339.82%5C%20m)
![\theta=-6.67^o](https://tex.z-dn.net/?f=%5Ctheta%3D-6.67%5Eo)
Explanation:
<u>Displacement
</u>
It's a vector magnitude that measures the space traveled by a particle between an initial and a final position. The total displacement can be obtained by adding the vectors of each individual displacement. In the case of two displacements:
![\vec r=\vec r_1+\vec r_2](https://tex.z-dn.net/?f=%5Cvec%20r%3D%5Cvec%20r_1%2B%5Cvec%20r_2)
Given a vector as its polar coordinates (r,\theta), the corresponding rectangular coordinates are computed with
![x=rcos\theta](https://tex.z-dn.net/?f=x%3Drcos%5Ctheta)
![y=rsin\theta](https://tex.z-dn.net/?f=y%3Drsin%5Ctheta)
And the vector is expressed as
![\vec z==](https://tex.z-dn.net/?f=%5Cvec%20z%3D%3Cx%2Cy%3E%3D%3Crcos%5Ctheta%2Crsin%5Ctheta%3E)
The monkey first makes a displacement given by (0.198 km,0°). The angle is 0 because it goes to the East, the zero-reference for angles. Thus the first displacement is
![\vec r_1==\ km=\ m](https://tex.z-dn.net/?f=%5Cvec%20r_1%3D%3C0.198cos0%5Eo%2C0.198sin0%5Eo%3E%3D%3C0.198%2C0%3E%5C%20km%3D%3C198%2C0%3E%5C%20m)
The second move is (145 m , -15.8°). The angle is negative because it points South of East. The second displacement is
![\vec r_2==\ m](https://tex.z-dn.net/?f=%5Cvec%20r_2%3D%3C145cos%28-15.8%5Eo%29%2C145sin%28-15.8%5Eo%29%3E%3D%3C139.52%2C-39.48%3E%5C%20m)
The total displacement is
![\vec r=\ m+\ m](https://tex.z-dn.net/?f=%5Cvec%20r%3D%3C198%2C0%3E%5C%20m%2B%3C139.52%2C-39.48%3E%5C%20m)
![\vec r=\ m](https://tex.z-dn.net/?f=%5Cvec%20r%3D%3C337.52%2C-39.48%3E%5C%20m)
In (magnitude,angle) form:
![|\vec r|=\sqrt{337.52^2+(-39.48)^2}=339.82\ m](https://tex.z-dn.net/?f=%7C%5Cvec%20r%7C%3D%5Csqrt%7B337.52%5E2%2B%28-39.48%29%5E2%7D%3D339.82%5C%20m)
![\boxed{|\vec r|=339.82\ m}](https://tex.z-dn.net/?f=%5Cboxed%7B%7C%5Cvec%20r%7C%3D339.82%5C%20m%7D)
![\displaystyle tan\theta=\frac{-39.48}{337.52}=-0.1169](https://tex.z-dn.net/?f=%5Cdisplaystyle%20tan%5Ctheta%3D%5Cfrac%7B-39.48%7D%7B337.52%7D%3D-0.1169)
![\boxed{\theta=-6.67^o}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctheta%3D-6.67%5Eo%7D)