9700 because 682 rounds to 700
Answer:
Less than Mercury's
Explanation:
According to third Kepler's law, the square of the planet's orbital period is proportional to the cube of the average orbital radius of the planet's orbit. The constant of proportionality depends only on the mass of the star, recall that 51 Peg has the same mass as the Sun. Since the orbital period of this planet is less than Mercury's, its average orbital radius is less than Mercury's.
<h2>
Answer:</h2>
If a car is rounding a flat curve, it experiences a centripetal force that pulls it towards the center of the circle it is rotating in.
Now,
The centripetal force can be balanced by the centrifugal force caused due to the acceleration of the body at the high speed which counters the centripetal force and in turn <u>prevents the car from slipping down the curve.</u>
So,
If the car doesn't hit the gas then the <em><u>car will fall down from the curve</u></em> as the Centripetal force will exceed the Centrifugal force of the car.
However, if the car doesn't hit the brake then the <em><u>car will maintain it's position on the flat curve</u></em> track as the centrifugal force will counter the effect of centripetal force directed towards the center.
Answer:
The time where the avergae speed equals the instaneous speed is T/2
Explanation:
The velocity of the car is:
v(t) = v0 + at
Where v0 is the initial speed and a is the constant acceleration.
Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:
v_ave = v0+a(T/2)
We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>
v(T/2)=v_ave
Now we want to know where the car should be, the osition of the car is:
Where x_A is the position of point A. Therefore, the car will be at:
<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>
