Calculate the resistance 50 feet of awg no. 12 solid copper wire round to nearest 0. 01 ohms.
1 answer:
The resistance of the conductor is 0.07940 Ohms.
<h3>What is the relation between resistance and area of wire?</h3>The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.
and it is formulated as:
where,
<em>p </em>- resistivity of the conductor (0.0214-ohm mm²/m)
R - resistance
l- length of conductor (50 feet) (15.24 m)
s - the area of the wire
Thus the resistance can be calculated as
R = 0.07940 Ohms.
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Explanation:
There are two forces acting on the water in the pail when it is at the top of its circular motion:
- The force of gravity, mg, acting downward (where m is the mass of the water and g the acceleration of gravity)
- The normal reaction, N also acting downward
Since the water is in circular motion, the net force must be equal to the centripetal force, so:
Where:
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When this occurs, the equation becomes:
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Answer:
The length of the tube is 3.92 m.
Explanation:
Given that,
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Length = 4 m
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Here,
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Answer:
The angle of incidence when the reflected ray is perpendicular to the incident ray = 45°
Explanation:
According to Snell's Law,
n₁ sin θ₁ = n₂ sin θ₂
When the angle between the incident ray and reflected ray is 90°, the angle of incidence is θ₁ and the angle of reflection, θ₂ = 90° - θ₁ and the index of refraction in the Snell's Law for both media would be the same, n₁ = n₂ = n
n sin θ₁ = n sin (90° - θ₁)
Note that from trigonometric relations,
Sin (90° - θ₁) = cos θ₁
n sin θ₁ = n cos θ₁
(sin θ₁)/(cos θ₁) = 1
tan θ₁ = 1
θ₁ = arctan 1 = 45°
Hope this Helps!!!
