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Natasha2012 [34]
1 year ago
11

Calculate the resistance 50 feet of awg no. 12 solid copper wire round to nearest 0. 01 ohms.

Physics
1 answer:
emmasim [6.3K]1 year ago
6 0

The resistance of the conductor is 0.07940 Ohms.

<h3>What is the relation between resistance and area of wire?</h3>

The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.

and it is formulated as:  

R=p\frac{l}{s}

where,

<em>p </em>- resistivity of the conductor (0.0214-ohm mm²/m)

R - resistance

l- length of conductor (50 feet) (15.24 m)

s - the area of the wire

Thus the resistance can be calculated as

R = 0.07940 Ohms.

Learn more about resistance here:

brainly.com/question/11431009

#SPJ4

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6 0
1 year ago
Pleaseeee Please help, I will love you forever and ever
matrenka [14]

Answer:

The answer to your question is

Explanation:

Data

mass = 0.5kg

T1 = 35

T2 = ?

Q = - 6.3 x 10⁴ J  = - 63000 J

Cp = 4184 J / kg°C

Formula

                        Q = mCp(T2 - T1)

                         T2 = T1 + Q/mCp    

Substitution

                       T2 = 35 - 63000/(0.5 x 4184)

                        T2 = 35 - 63000/2092

                        T2 = 35 - 30.1

                         T2 = 4.9 °C

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\boxed{ \bold{ \boxed{ \sf{see \: below}}}}

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MA ( Mechanical Advantage ) is always less than VR ( Velocity Ratio ) because <u>MA</u><u> </u><u>is</u><u> </u><u>reduced</u><u> </u><u>by</u><u> </u><u>friction</u><u> </u><u>but</u><u> </u><u>VR</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>affected</u><u> </u><u>by</u><u> </u><u>friction</u><u>.</u>

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