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Roman55 [17]
3 years ago
14

Explain whether or not it is easy to recycle electronics now

Chemistry
2 answers:
Lady_Fox [76]3 years ago
6 0

Answer:

It is indeed Difficult to Recycle Electronics

Electronics recycling is not the same as recycling cardboard. These items are difficult to recycle. Recycling properly and safely typically costs more than the materials are worth.

<em>Hope this helps!</em>

Karolina [17]3 years ago
5 0

\color{blue} \colorbox{lime}{ \boxed{ \boxed{ \sf{✒ QUESTION:}}}}

<h3>Explain whether or not it is easy to recycle electronics now</h3>

\color{blue} \colorbox{lime}{ \boxed{ \boxed{ \sf{✒ANSWER:}}}}

Electronics are Difficult To Recycle

  • Recycling electronics isn't like recycling cardboard. These products are not easy to recycle. Proper and safe recycling often costs more money than the materials are worth.
  • The process of recycling can vary depending on the materials being recycled and the technologies used. Once electronics are picked up and transported to the recycling center then materials in the e-waste stream must be processed and separated. ... Next, the e-waste is shredded and plastics and metals are separated
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2. A student has a centrifuge tube containing 14.0 g of t-butanol and is asked to make a 1.2 m solution of ethanol/t-butanol. Ho
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Answer:

0.774g of ethanol

0.970mL of ethanol

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Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.

In the problem, you need to prepare a 1.2m solution of ethanol (Solute) in t-butanol (solvent).

14.0g of butanol are <em>0.014kg </em>and as you want to prepare the 1.2m solution, you need to add:

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8 0
3 years ago
At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
wariber [46]

Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

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3 years ago
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