Answer:
i think it's D tbh, just cus it was the scientist who did the work
Answer:
1 mole of lithium is 7 grams. we know this from it's relative molecular mass.
if 1 mole is 7 grams then x moles is 0.56 grams
we can equate them by saying (1/x)=(7/0.56)
after cross multiplying, we get 7x=0.56, x will be equals to 0.56/7
x=0.08 grams
It seems that you have missed the necessary options for us to answer this question so I had to look for it. But anyway, here is the answer. If Dr. John Sutherland is correct, the one that was necessary <span> for inert carbon atoms to become part of the chemistry of earth is CYANIDE. Hope this helps.</span>
Answer:
b. The nitrogen atom shares one valence electron with each iodine atom, which also shares one valence electron each with the nitrogen atom.
Explanation:
The formula of nitrogen triiodide is NI3. In this compound, the nitrogen atom shares one valence electron with each chlorine atom which in turn also shares a valence electron with nitrogen.
Recall that covalent bonding involves a sharing of <u>valence </u> electrons. Transfer of electrons is typical of ionic bonds between a metal and a nonmetal. nitrogen and iodine are nonmetals hence they bond covalently.
Hence, the formation of NI3 leaves three lone pairs on each chlorine atom and one lone pair on the nitrogen atom.
Answer:
x²+6x+5=0
On comparing with the equation
ax² + bx + c = 0
a=1, b = 6 and c = 5
Now
b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16
![x = \frac{ - b \:± \: \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - 6\:± \: \sqrt{16 } }{2 \times 1} \\ \\ x = \frac{ - 6± {4} }{2} \\ \\ x = \frac{ - 6 + {4} }{2} \: \: or \: \: x = \frac{ - 6 - {4} }{2} \\ \\ \implies \: x = \frac{ \cancel-2 }{ \cancel2}^{-1 }\: \: or \: \: x = \frac{ \cancel-10 }{ \cancel2}^{-5}\\ \\ \implies \: { \blue{\fbox{ \: x = - 1 \: \: \: or \: \: \:x = - 5}}}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%20b%20%5C%3A%C2%B1%20%5C%3A%20%20%5Csqrt%7Bb%20%7B%7D%5E%7B2%7D%20-%204ac%20%7D%20%20%7D%7B2a%7D%20%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20-%206%5C%3A%C2%B1%20%5C%3A%20%20%5Csqrt%7B16%20%7D%20%20%7D%7B2%20%5Ctimes%201%7D%20%20%5C%5C%20%5C%5C%20%20x%20%3D%20%20%5Cfrac%7B%20-%206%C2%B1%20%7B4%7D%20%20%7D%7B2%7D%20%20%5C%5C%20%20%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20-%206%20%2B%20%20%7B4%7D%20%20%7D%7B2%7D%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20x%20%3D%20%20%5Cfrac%7B%20-%206%20-%20%20%7B4%7D%20%20%7D%7B2%7D%20%5C%5C%20%20%20%5C%5C%20%5Cimplies%20%5C%3A%20x%20%3D%20%20%5Cfrac%7B%20%20%5Ccancel-2%20%20%7D%7B%20%5Ccancel2%7D%5E%7B-1%20%7D%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20x%20%3D%20%20%5Cfrac%7B%20%20%5Ccancel-10%20%20%7D%7B%20%5Ccancel2%7D%5E%7B-5%7D%5C%5C%20%20%5C%5C%20%20%20%20%5Cimplies%20%5C%3A%20%7B%20%5Cblue%7B%5Cfbox%7B%20%5C%3A%20x%20%3D%20%20-%201%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20%20%5C%3Ax%20%20%3D%20%20-%205%7D%7D%7D)