The answer is definitely not 70.923
Answer:
The most common non-destructive visualization method for TLC plates is ultraviolet (UV) light. A UV lamp can be used to shine either short-waved (254nm) or long-waved (365nm) ultraviolet light on a TLC plate with the touch of a button
Explanation:
hope this helps
Answer:
Detail is given below.
Explanation:
Similarities:
All are the forms of matter.
Solid, liquid and gases are made up of ions, atoms and molecules.
They have shape and volume.
Molecules in Liquid and solid are closer to each others.
Liquid and gases can flow very easily.
Liquid and solid both can not compressed very easily.
Differences:
Molecule of gases randomly move everywhere and occupy all available space but liquid and solid's molecules are not move as much easier as molecules of gases can.
The density of gases are very low as compared to the liquid and solid.
Gas molecules are at long distance from each other while in liquid and solid they are closer to each other.
The very weak inter molecular forces are present between gas molecules as compared to the liquid and solids.
Solids have definite volume and shape but liquid and gases acquire the shape of container.
In solids molecules are tightly pack and very close to each other while in liquid molecules are not tightly pack like in case of solid.
The densities of solids are also very high as compared to the liquid and gas.
There are very strong inter molecular forces are present between solid molecules.
Answer:
the sing post
Explanation:
because the reference frame is a fixed object that determines whether a body is in motion or not so the other passengers are fixed but relative to the the the man is at rest but relative to the sign post it is in the motion, did I get me, sister
The answer is 19.9 grams cadmium.
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
heat lost by cadmium = heat gained by the water
-qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
-qcadmium = qwater
-(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
mcadmium = 19.9 grams
