Outside, because there is more space for it to go, and there is nothing stopping the water from going straight up into the sky.
Answer:
a) The volume increases
b) The volume decreases
c) The volume does not change
Explanation:
<em>A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas.</em>
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When there is a change in the pressure (P) at constant temperature (T) and amount of gas (n), we can find the change in the volume (V) using Boyle's law.
P₁.V₁ = P₂.V₂
where,
1 refer to the initial state
2 refer to the final state
<em>a) The pressure drops to 0.40 atm.</em>
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (0.40 atm) . V₂
V₂ = 5 . V₁
The volume increases.
<em>b) The pressure increases to 6.0 atm.</em>
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (6.0 atm) . V₂
V₂ = 0.33 . V₁
The volume decreases.
<em>c) The pressure remains at 2.0 atm.</em>
P₁.V₁ = P₂.V₂
(2.0 atm) . V₁ = (2.0 atm) . V₂
V₂ = V₁
The volume does not change.
In this question, you are asked to find two condition which was:
1. Same phase at STP( standard temperature and pressure)
2. Different structure and properties
In option 1 and 4 the phase of the element is different. It was solid+gas for option 1 and solid+liquid for option 4. That clearly not fulfills the first condition.
At STP helium is gas but mercury should be liquid, not gas. That means option 3 won't fulfill the 1st condition too.
Option 2 is true since both of them gas and their structure and properties are different. One example of properties is that oxygen doesn't have an odor but ozone has.
The solid that comes out of a solution is called precipitate