Question

Calculate the energy of a proton of light with a frequency of 8.5x1014 Hz.

Answer 1

Answer:

$\huge{5.632 \times {10}^{ - 19} \: J}$

Explanation:

The energy of the proton can be found by using the formula

E = hf

where

E is the energy in J

f is the frequency in Hz

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question we have

E = 6.626 × 10-³⁴ × 8.5 × 10¹⁴

We have the final answer as

$5.632 \times {10}^{ - 19} \:J$

Hope this helps you