The answer to the question is 84
(Step By Step Explanation).
P1 V1/T1= P2 V2/T2
::0.75 x 120/295 = 1.25 x V2/345
90/295= 1.25V2/345
(cross multiply )
1.25V2 x 295 = 90 x 345
368.75V2 = 31050
(divide by the coefficient of the unknown) .
368.75V2/368.75 = 31050/368.75
V2 = 84.2. = 84
::The volume is 82.
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Answer:
Pretty sure its B sorry if im wrong
Explanation:
Answer:
a. Combustion.
b. 
c. 
Explanation:
Hello.
a. In this case, given the reaction by which propane is converted into carbon dioxide and water:

It is known as a combustion reaction since it is about a fuel (here propane) which is burnt by the oxygen contained in the air (21%).
b. Since the carbon dioxide contains all the carbon in the products based on the law of conservation of mass, the yielded grams are computed via a mole mass relationship:

Since 44 grams of carbon dioxide contain 12 grams of carbon.
c. As well as b., all the hydrogen is given off in form of water, thus, the required mass turns out:

Since 18 grams of water contain 2 grams of hydrogen.
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Answer:
114 K
Explanation:
Given data
- Volume of oxygen (V): 629 mL = 0.629 L
- Pressure of oxygen (P): 0.500 atm
- Moles of oxygen (n): 0.0337 mol
We can calculate the temperature at which the student collected the oxygen using the ideal gas equation.

The oxygen gas was collected at 114 K.
Formula: % by mass = (mass of solute / mass of solution] *100
Data:
mass of solution = 80.85 g
% by mass = 22.4%
Unknown = mass of solute
Solution
% by mass = (mass of solute / mass of solution] *100 = >
mass of solute = % by mass * mass of solution / 100
mass of solute = 22.4 * 80.85 / 100 = 18.11 g
Answer: 18.11 g