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malfutka [58]
3 years ago
7

PLEASE HELP FAST!!!! I'll give brainliest to the best answer!!

Chemistry
2 answers:
yarga [219]3 years ago
8 0
A concentrated acid is a stronger acid
MArishka [77]3 years ago
7 0

Answer:

A concentrated acid is an acid which is in either pure form or has a high concentration. Laboratory type sulfuric acid (about 98% by weight) is a concentrated (and strong) acid. A dilute acid is that in which the concentration of the water mixed in the acid is higher than the concentration of the acid itself.

Explanation:

Concentrated acid - Those acids which are pure or have very high concentration in water are called as concentrated acids. For example concentrated Hydrochloric acid (HCl) and concentrated Sulphuric acid are examples of concentrated acids.

You might be interested in
A sample of gas occupies a volume of 120.0 mL at a pressure of 0.75 atm and a temperature of 295 K. What will the volume be at a
MakcuM [25]
The answer to the question is 84
(Step By Step Explanation).
P1 V1/T1= P2 V2/T2
::0.75 x 120/295 = 1.25 x V2/345
90/295= 1.25V2/345
(cross multiply )
1.25V2 x 295 = 90 x 345
368.75V2 = 31050
(divide by the coefficient of the unknown) .
368.75V2/368.75 = 31050/368.75
V2 = 84.2. = 84
::The volume is 82.
Mark As brainliest
6 0
4 years ago
Please help me out! :))
Leto [7]

Answer:

Pretty sure its B sorry if im wrong

Explanation:

4 0
3 years ago
Help I need to show work!
lubasha [3.4K]

Answer:

a. Combustion.

b. m_C=3.057gC

c. m_H=3.67gH

Explanation:

Hello.

a. In this case, given the reaction by which propane is converted into carbon dioxide and water:

C_3H_8+5O_2 \rightarrow 3CO_2+4H_2O

It is known as a combustion reaction since it is about a fuel (here propane) which is burnt by the oxygen contained in the air (21%).

b. Since the carbon dioxide contains all the carbon in the products based on the law of conservation of mass, the yielded grams are computed via a mole mass relationship:

m_C=11.21gCO_2*\frac{12gC}{44gCO_2}=3.057gC

Since 44 grams of carbon dioxide contain 12 grams of carbon.

c. As well as b., all the hydrogen is  given off in form of water, thus, the required mass turns out:

m_H=33.0gH_2O*\frac{2gH}{18gH_2O}=3.67gH

Since 18 grams of water contain 2 grams of hydrogen.

Best regards.

6 0
3 years ago
A student collects 629ml of oxygen at 0.500at, the student collected 0.0337 moles. At what temperature did the student collect t
VashaNatasha [74]

Answer:

114 K

Explanation:

Given data

  • Volume of oxygen (V): 629 mL = 0.629 L
  • Pressure of oxygen (P): 0.500 atm
  • Moles of oxygen (n): 0.0337 mol
  • Temperature (T): ?

We can calculate the temperature at which the student collected the oxygen using the ideal gas equation.

P \times V = n \times R \times T\\T = \frac{P \times V}{n \times R}  = \frac{0.500atm \times 0.629L}{0.0337mol \times 0.0821atm.L/mol.K} = 114 K

The oxygen gas was collected at 114 K.

4 0
3 years ago
Read 2 more answers
What mass of mgf2 is contained in 80.85 g of a 22.4% by mass solution of mgf2 in water?
Aleks [24]
Formula: % by mass = (mass of solute / mass of solution] *100

Data:

mass of solution = 80.85 g

% by mass = 22.4%

Unknown = mass of solute

Solution

% by mass = (mass of solute / mass of solution] *100 = >

mass of solute = % by mass * mass of solution / 100

mass of solute = 22.4 * 80.85 / 100 = 18.11 g

Answer: 18.11 g
4 0
3 years ago
Read 2 more answers
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