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3 years ago

6

What can you say about The relationship between mass and terminal velocity ?

1 answer:

sergiy2304 [10]3 years ago

4 0

Answer:

Take a rubber kick ball and a bowling ball. What happens if you throw them both off a bridge? Despite having the same shape as the rubber ball, the bowling ball has a lot more mass and falls faster. Why? Because the bowling ball's speed, combined including its form, provides a resistive force in the direction it's traveling; because the bowling ball weighs more, the force Earth's gravity pulls on it is greater - and it takes more air resistance to reach terminal velocity than the rubber ball; and because the bowling ball weighs more, the force Earth's gravity pulls on it is greater - and it takes more air pressure to reach terminal velocity than the rubber ball.

With the same area but substantially less mass, the rubber ball requires less resistance to slow down to terminal velocity.

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A baseball has a mass of 0.15kg .What is the net force on the ball if it's acceleration is 40.0m/sw

kvasek [131]

By Newton's second law, we have

$F=ma$

So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of

$F=0.15\cdot 40 = 6N$

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4 years ago

What is the maximum height to which a motor

Natasha_Volkova [10]

Answer:

4.16 m

Explanation:

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3 years ago

What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

kkurt [141]

Answer:

$4.3\cdot 10^{-12} J$

Explanation:

The fusion reaction in this problem is

$4^1_1H \rightarrow ^4_2He +2e^+$

The total energy released in the fusion reaction is given by

$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

The conversion factor between atomic mass units and kilograms is

$1u=1.66054\cdot 10^{-27}kg$

So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

$\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J$

6 0

3 years ago

A car of mass 2400kg accelerates from 10m/s to 30m/s if the force is 12000N what is the distance

leonid [27]

Explanation:

Initial velocity (u) = 10 m/s
Final velocity (v) = 30 m/s
Mass (m) = 2400 kg
Force (F) = 12000 N

Let us find the time taken first.

→ F = ma

Acceleration (a) = (v – u)/t

→ 12000 = 2400 × (30 – 10)/t

→ 12000 ÷ 2400 = (20)/t

→ 5 = 20/t

→ 5t = 20

→ t = 20 ÷ 5

→ <u>t</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>seconds</u>

Now, find the acceleration.

→ a = (v – u)/t

→ a = (30 – 10)/4

→ a = 20/4

→ <u>a</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>m</u><u>/</u><u>s²</u>

Now, by using the third equation of motion,

→ v² – u² = 2as

s = distance

→ (30)² – (10)² = 2 × 5 × s

→ 900 – 100 = 10s

→ 800 = 10s

→ 800 ÷ 10 = s

→ <u>8</u><u>0</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>s</u>

Therefore, distance travelled is 80 m.

4 0

4 years ago

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olga_2 [115]

A. long-wave radiation occupies a smaller percentage than short-wave radiation

5 0

4 years ago

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