Whats the boolean expression of this circuit?
1 answer:
Answer:
G8 = x0'x2' +x0'x3' +x1x2
Explanation:
The expression can be written different ways, depending on the need to avoid hazards. One of them is ...
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A truth table and Karnaugh map are shown for the circuit. The terms used in the Boolean expression come from the corners, the upper half of the left- and right-columns, and the right half of the middle two rows. If a static hazard is to be avoided, a term x1x0' could be added representing the right column.
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Answer:
28,8 m/s
Explanation:
In a steady flow system we can say that m1=m2 which means that the mass flow in the entrance in the same in the outlet. m is flow (kg/s)
we know that where V (m/s) is velocity, A (m^2) ia area and v is specific volume (m^3/kg)
Since m1=m2 we can say
clearing the equation
we can specific volume (m^3/kg) from thermodynamic tables
for the entrance is 400°C and 4 MPa is superheated steam and v is : 0,7343 m^3/kg
In the outlet we have saturated vapor with quality (x) of 80%. In this case we get the specific saturated volume for the liquid (vf) and the specific volume for the saturated (vg) gas from the thermodynamic tables. we use the next equation to get (v) for the condition of interest, in this case 80% quality.
v= vf +x*(vg - vf)
where:
x: quality
vf = liquid-saturated-specific-volume
vg =steam-saturated-specific-volume.
for this problem
x = 0,8
vf = 0,00102991
vg = 3,24015
so
we get = 2,593 m^3/kg
The area is the one for a circle
r1 = 0,1 m^2 for area 1
r2=0,5 m^2 for area 2
A1 = 0,0314 m^2
A2 = 0,7853 m^2
we know that V1 is 20 m/s
replacing these values in the equation
we get V2 = 28,2 m/s.