Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.
2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O
1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O
Empirical formula
H2SO4
Answer & Explanation:
- The neutralization of H₂SO₄ with NaOH is occurred according to the balanced equation:
<em>H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O,</em>
It is clear that every 1.0 mol of H₂SO₄ needs 2 mol of NaOH to be neutralized completely.
<em>So, when you mix one mole of sulfuric acid with 1 mole of sodium hydroxide, there will be an excess of sulfuric acid.</em>
<em>Thus, the pH of the solution remain below 7.</em>
A high concentration of water has <u>fewer</u> dissolved particles than a low water concentration.
Most cell membranes are not as easily permeable to many dissolved compounds as water is. There is a quick and constant flow of water. From one area with less dissolved matter to another with more, water transports NET. Or, if you want, from an area with a lot of water to one with little water. The terms isotonic, hypotonic, and hypertonic refer to the concentration of dissolved material. In a medium, such as the extracellular fluid, every distinct material has a concentration gradient that is unique from the gradients of other substances. Every substance will diffuse in line with that gradient as well.
Learn more about Concentration here-
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Those elements with similar properties are in the same column.
