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8_murik_8 [283]
2 years ago
6

How does energy flow through the food chain?

Chemistry
2 answers:
Delicious77 [7]2 years ago
6 0

Answer:

So, energy is really all one big circle. Think of it like this:

When an organism dies, it's body is always inevitably taken back by the earth. For the purpose of the example, we'll use one specific scavenger as the main contributor here. When the body soaks back into the soil, the nutrients act as a fertilizer and aid in the growth of a patch of grass, that grass is eaten by a grasshopper, then, a frog comes along and is eaten by a snake, and eventually, that snake is eaten by an eagle. Let's say that eagle dies of natural causes, and once it passes away, the earth reclaims it's body. Now, we have a whole new fresh patch of grass and the cycle continues on, and on, and on. In this way, all energy is made eternal through the cycle of life and the food chain.

yuradex [85]2 years ago
3 0

Answer:

2nd order.

Explanation:

gras, grasshopper, frog, snake, eagle

Pleas mark branliest if you are satisfied with the answer. Thanking you in anticipation.

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Lonization Energy decreases as you go down a family (group or column). Explain why this pattern
Goryan [66]

Answer:

Explanation:

As you move down a group, first ionization energy decreases. WHY? Electrons are further from the nucleus and thus easier to remove the outermost one.

3 0
3 years ago
If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, what is the heat flow abs
Arisa [49]

If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.

<h3>What is entropy? </h3>

The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.

Unit of entropy = J/K

<h3>Formula:</h3>

∆s = ∆Q/T

where,

∆s = change in entropy of the surrounding = -326J/K

∆Q = heat absorbed from surrounding

T = Temperature = 451K

∆Q = ∆s × T

∆Q = -326 × 451

∆Q = 147,026 J

∆Q = 147.026 kJ

Thus we find that the heat absorbed by the system is 147.026 kJ.

learn more about entropy:

brainly.com/question/14131507

#SPJ1

8 0
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a hopefully this is helpful

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Name two elements that you would expect to have properties very much like those of calcium
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Beryllium, magnesium, strontium, barium, or radium. Hope this helped :))
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It's called radiation
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