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denis-greek [22]
3 years ago
10

Please help me thanks so much

Chemistry
2 answers:
ASHA 777 [7]3 years ago
6 0

Answer:

a switch

Explanation:

Eduardwww [97]3 years ago
6 0

Answer:

a switch is the answer hope it helps

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Calculate the percent ionization of 1.60 M aqueous acetic acid solution. For acetic acid, Ka=1.8×10−5.
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Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v
Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

Db = Mb/Vb (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: Vb = Vg + Vk (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

Db = (Mg + Mk) / (Vg + Vk)

Db = (Dg * Vg + Dk * Vk)/(Vg + Vk) (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

SG = Substance Density / Reference Density

Therefore:

Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)

SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)

SGb * (Vg + Vk) = SGg * Vg + SGk * Vk

SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk

Replacing with the Specific Gravity data, we obtain:

0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk

0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk

0.07 * Vg = 0.05 * Vk

Vg/Vk = 0.05/0.07

Vg/Vk = 0.71

8 0
2 years ago
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