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aksik [14]
3 years ago
6

A 10 kg gun recoils with a speed of 0.1 m/s after it fires a 0.001 kg bullet. What is the speed of the bullet?

Physics
1 answer:
Kitty [74]3 years ago
3 0

As we know that here gun + bullet system is isolated from all other external force system

so here the momentum of system is always conserved

so we will say

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

here we know that

v_{1i} = v_{2i} = 0

m_1 = 10 kg

m_2 = 0.001kg

v_{1f} = 0.1 m/s

now we will have

0 + 0 = 10(0.1) + 0.001v_{2f}

by solving above equation we will have

v_{2f} = 1000 m/s

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A mass M tied to a light string is moving in a vertical circle. The tension in the string at the top is TT and TB at the bottom
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Answer:

Explanation:

Tension provides centripetal force in the circular motion . In circular motion work done by force = torque x angle

torque is zero as , centripetal force passes through axis of rotation that is center.

So work done by centripetal force  = 0

So work done by tension on M = 0

5 0
3 years ago
When a ray of light is incident normally on an air glass interface what is its angle of refraction​
DiKsa [7]

Answer:

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3 0
2 years ago
A robot on a basketball court needs to throw the ball in the hoop. The ball have a velocity of 10 m/s and an an angle of 60 degr
IRISSAK [1]

Answer:

Initial velocity = 10 m/s

θ = 60°

This is the case of projectile motion

So the horizontal component of velocity 10 m/s  =  10 cosθ

u = 10 cosθ

u = 10 cos 60°

u=5 m/s

x= 5 m

So in the horizontal direction

x = u .t

5 = 5 .t

t = 1 sec  The vertical component of velocity 10 m/s = 10 sinθ

Vo= 10 sinθ

Vo= 10 sin 60°

Vo = 8.66 m/s

V^2=V_o^2+2gh

0=V_o^2-2gh

0=8.66^2-2\times 10\times h

h=3.75 m

So height of robot = 3.75 - 0.75 m

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5 0
3 years ago
a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the run
Sergio039 [100]

Answer:

The runner's acceleration was 1\ m/s^2

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:

\displaystyle a=\frac{9-5}{4}

\displaystyle a=\frac{4}{4}=1

The runner's acceleration was 1\ m/s^2

5 0
3 years ago
Besides the force due to gravity or g, what else determines the period of a pendulum?
pochemuha
Length of the cord..........................................................

6 0
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