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jeyben [28]
3 years ago
10

5. Layer of Earth consisting of crust & upper layer of mantle ________

Physics
2 answers:
elixir [45]3 years ago
6 0

Answer:

lithosphere

Explanation:

hope this helps you!!

dedylja [7]3 years ago
6 0

Answer:

the answer is lithosphere

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A sailboat weighing 980 lb with its occupants is running downwind at 8 mi/h when its spinnaker is raised to increase its speed.
Effectus [21]

Answer:

78.498N

Explanation:

The Net force provided by the spinnaker can be obtained from Newton's second law of motion as follows;

F=\frac{m(v-u)}{t}................(1)

where m is the mass, v is the final velocity, u is the initial velocity and t is the time interval for which the force acted.

Given;

m =980lb

v = 12mi/h

u =8mi/hr

t = 10s.

It is important to convert all quantities to their SI units where necessary, so we do that as follows;

1lb = 0.45kg,

hence 980lb = 980 x 0.45kg = 441kg.

1mile = 1609.34m

1hour = 3600s,

therefore;

8mi/h=\frac{8*1609.34m}{3600s}=3.58m/s

12mi/h=\frac{12*1609.34m}{3600s}=5.36m/s

Substituting all values into equation (1), we obtain the following;

F=\frac{441(5.36-3.58)}{10}\\F=\frac{441*1.78}{10}\\F=\frac{784.98}{10}\\F=78.498N

4 0
3 years ago
If a diode at 300°K with a constant bias current of 100μA has a forward voltage of 700mV across it, what will the voltage drop a
MAVERICK [17]

Answer:

the voltage drop across this same diode will be 760 mV

Explanation:

Given that:

Temperature T = 300°K

current I_1 = 100 μA

current I_2 = 1 mA

forward voltage V_r = 700 mV = 0.7 V

To objective is to find the voltage drop across this same diode  if the bias current is increased to 1mA.

Using the formula:

I = I_o \begin {pmatrix}  e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}

I_1 = I_o \begin {pmatrix}  e^{\dfrac{V_r}{nv_T}-1} \end {pmatrix}

where;

V_r = 0.7

I_1 = I_o \begin {pmatrix}  e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix}

I_2 = I_o \begin {pmatrix}  e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix}

\dfrac{I_1}{I_2} = \dfrac{ I_o \begin {pmatrix}  e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{  I_o \begin {pmatrix}  e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }

\dfrac{100 \ \mu A}{1 \ mA} = \dfrac{ \begin {pmatrix}  e^{\dfrac{0.7}{nv_T}-1} \end {pmatrix} }{  \begin {pmatrix}  e^{\dfrac{V_r'}{nv_T}-1} \end {pmatrix} }

Suppose n = 1

V_T = \dfrac{T}{11600} \\ \\ V_T = \dfrac{300}{11600} \\ \\ V_T = 25. 86 \ mV

Then;

e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix}  e ^{\dfrac{ 0.7} { nV_T} -1} \end {pmatrix}

e^{\dfrac{V_r'}{nv_T}-1} = 10 \begin {pmatrix}  e ^{\dfrac{ 0.7} { 25.86} -1} \end {pmatrix}

e^{\dfrac{V_r'}{nv_T}-1} = 5.699 \times 10^{12}

{e^\dfrac{V_r'}{nv_T}} = 5.7 \times 10^{12}

{\dfrac{V_r'}{nv_T}} =log_{e ^{5.7 \times 10^{12}}}

{\dfrac{V_r'}{nv_T}} =29.37

V_r'=29.37 \times nV_T

V_r'=29.37 \times 25.86

V_r'=759.5 \ mV

Vr' \simeq 760 mV

Thus, the voltage drop across this same diode will be 760 mV

3 0
3 years ago
A penny falls from a windowsill which is 25.0 m above the sidewalk. How much time does a passerby on the sidewalk below have to
Yanka [14]
You need to know the formula:

25 = 1/2 * g * t^2

t = √(50/g) = 2.258 s, where I use g = 9.8 m/s^2
4 0
4 years ago
Only living things have energy T or F?
Angelina_Jolie [31]

Answer:

. living things only have energy : true.

8 0
2 years ago
Read 2 more answers
All objects in our solar system orbit the Sun. How is the movement of planets like
seraphim [82]

Answer:

planets move in elliptical orbit.

Explanation:

this is because planets are formed closer to the sun while the comets are formed further.

4 0
3 years ago
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