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Harman [31]
3 years ago
11

Using venn diagram, compare and contrast cotton balls and pine cones

Chemistry
1 answer:
Irina-Kira [14]3 years ago
8 0
Cotton Balls are soft and pine cones are hard.
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How many grams of water are contained in a 0.127 l sample at 20°c?
kvasek [131]

The density of water at 20 °C is 0.9982 g/cm^{3} or 998.2 g/L. The volume of water is 0.127 L thus, its mass can be calculated from the following formula:

d=\frac{m}{V}

Here, d is density, m is mass and V is volume of water.

On rearranging,

m=d×V=(998.2 g/L)(0.127 L)=126.7 g

Thus, mass of water is 126.7 g.


3 0
3 years ago
Is iron conductive in water?
Rudik [331]

Answer: yes

Explanation: it is always in a conductive state

4 0
2 years ago
Read 2 more answers
The value of Ka for phenol (a weak acid), C6H5OH, is 1.00×10-10. Write the equation for the reaction that goes with this equilib
I am Lyosha [343]

Answer:

Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}

Explanation:

Hello,

In this case, weak acids are characterized by the fact they do not dissociate completely, it means they do not divide into the conjugated base and acid at all, a percent only, which is quantified via equilibrium. In such a way, the chemical equation representing such incomplete dissociation is said to be:

C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+

Thus, we can write the law of mass action, which consider the equilibrium concentrations of all the involved species, which is also known as the acid dissociation constant which accounts for the capacity the acid has to yield hydronium ions:

K=Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}

Best regards.

3 0
3 years ago
What do element; atoms; molecule; chemical bond; compound; mixture; and substance have in common
sleet_krkn [62]
They are all things you can do to elements on the periodic table?
7 0
3 years ago
Calculate the following:
d1i1m1o1n [39]

Answer:

Explanation:

1) Given data:

Number of moles of lead = 4.3×10⁻³ mol

Mass of lead = ?

Solution:

Mass = number of moles × molar mass

Molar mass of lead = 207.2 g/mol

Mass = 4.3×10⁻³ mol × 207.2 g/mol

Mass =  890.96 g

2) Given data:

Number of atoms of antimony = 3.8×10²² atoms

Mass of antimony = ?

Solution:

1 mole contain 6.022 ×10²³ atoms

3.8×10²² atoms × 1 mol / 6.022 ×10²³ atoms

0.63×10⁻¹ mol

0.063 mol

Mass = number of moles × molar mass

Molar mass of lead = 121.76 g/mol

Mass = 0.063 mol ×  121.76 g/mol

Mass =  7.67 g

3) Given data:

Mass of tungsten = 15.5 Kg (15.5 kg × 1000 g/ 1kg = 15500 g)

Number of atoms = ?

Solution:

Number of moles of tungsten:

Number of moles = mass/molar mass

Number of moles = 15500 g / 183.84 g/mol

Number of moles = 84.3 mol

1 mole contain 6.022 ×10²³ atoms

84.3 mol  × 6.022 ×10²³ atoms / 1mol

507.65 ×10²³ atoms

8 0
3 years ago
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