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2 years ago

Help Please!!!!!!!!!!!!!!!!!!

Physics

1 answer:

julia-pushkina [17]2 years ago

4 0

The answer is 59.4 degrees.

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What is the origin of magma

sveta [45]

Magma forms by partial melting of upper mantle and crust. Partial melt means that only a fraction of the available material forms a melt, and that the remainder stays solid. The partial melt rises because of its lower density and ascends through he crust.

6 0

3 years ago

Read 2 more answers

17. Matthew has a piece of wood with mass of 278 g and a volume of 375 cm^3. What is the wood’s density? a. Step 1: Formula ____

Keith_Richards [23]

Answer:

Density =0.74 $g/cm^{3}$

Explanation:

Step 1: Formula

$Density=\frac{Mass}{Volume}$

Step 2: Data

m=278 g

v=375 $cm^{3}$

Step 3:Solve

d= $\frac{278}{375}$ $g/cm^{3}$

d=0.74 $g/cm^{3}$

8 0

2 years ago

Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of

Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

$s = at^2/2 = 5t^2/2 = 2.5t^2$

We can take derivative of this with respect to time t to get the equation of slope:

$s' = (2.5t^2)' = 2*2.5t = 5t$

As time t increase, the slope would increases with time as well.

6 0

3 years ago

Who is responsible of refraction light 1/3 in eye

alexandr1967 [171]

The cornea is responsible of refraction light 1/3 in eye.

<h3>What is the function of the cornea?</h3>

In addition to the protective function, it plays a fundamental role in the formation of vision. Transparent, it works like a lens over the iris, focusing light from the pupil towards the retina.

Normally, the cornea and lens deflect (refract) incoming light rays, focusing them on the retina. The shape of the cornea is fixed, but the lens changes shape to focus on objects at different distances from the eye.

See more about cornea at brainly.com/question/2297282

#SPJ12

3 0

2 years ago

Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector

Sav [38]

Good morning.

We see that $\mathsf{\overset{\to}{b}} = \mathsf{(4.00, \ 4.00, \ 2.00)}$

The magnitude(norm, to be precise) can be calculated the following way:

$\star \ \boxed{\mathsf{\overset{\to}{a}=(x, y,z)\Rightarrow ||\overset{\to}{a}|| = \sqrt{x^2+y^2+z^2}}}$

Now the calculus is trivial:

$\mathsf{\|\overset{\to}{b} \| =\sqrt{4^2+4^2+2^2} =\sqrt{16+16+4}}\\ \\ \mathsf{\|\overset{\to}{b}\|=\sqrt{36}}\\ \\ \boxed{\mathsf{\|\overset{\to}{b}\| = 6.00 \ u}}$

7 0

3 years ago