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vodomira [7]
3 years ago
11

A curve in a stretch of highway has radius R. The road is not banked in any way. The coefficient of static friction between the

tires and the road is . What is the fastest speed that a car can safely travel around the curve
Physics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

maximum possible velocity = \sqrt{ugR}

Explanation:

centripetal acceleration when the  car is going in the circle must be less than the maximum friction for the car to not slip.

centripetal acceleration \frac{mv^{2}}{r}

where v is the velocity of car and r is the radius of circle

maximum friction = umg

where u is the coefficient of static friction.

thereforeumg\geq \frac{mv^{2}}{R}

therefore maximum possible velocity = \sqrt{ugR}

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We need to draw a coordinates. the east and south should be the north vector for horizontal line 50 KM in distance is zero. the south is a negative. the south east and north west we should draw the 45 degrees angle in the approprate quadrant and then use the 1-1-sqrt(2) have a relationship in 45-45-90 triangles to resolve the N/S, E/W components.

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6 0
3 years ago
2
Zanzabum

Tires aren't made from pure rubber because it makes the weight higher which increases the engine load.

<h3>What is Tyre?</h3>

This is defined as a piece of rubber which is attached to the wheels of automobiles for movement.

Pure rubber isn't used to make tyres because it has a higher weight which increases the engine load thereby making the vehicle slower.

Read more about Tyre here brainly.com/question/24332515

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5 0
2 years ago
A solid aluminum cube has sides each of length L . A second cube of the same material has sides two times the length of the firs
Dmitrij [34]
Density is a material property, so the second cube will have the same density as the first.
8 0
3 years ago
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at 1 p.m. a car traveling at a constant velocity of 78 km per hour towards the West it's 34 km to the west of our school how far
Fittoniya [83]

83 km/h * 2.5 hours (3:30 - 1:00) = 207.5 km  

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3 0
3 years ago
Suppose a 48-N sled is resting on packed snow. The coefficient of kinetic friction is 0.10. If a person weighing 660 N sits on t
Annette [7]

Assume the snow is uniform, and horizontal.

Given:

coefficient of kinetic friction = 0.10 = muK

weight of sled = 48 N

weight of rider = 660 N

normal force on of sled with rider = 48+660 N = 708 N = N

Force required to maintain a uniform speed

= coefficient of kinetic friction * normal force

= muK * N

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=70.8 N


Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.


8 0
3 years ago
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