A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
1 answer:
The final speed of the combined masses is 0.21 m/s
Applying the law of conservation of momentum:
Total momentum before collision = Total momentum after collision.
⇒ Formula:
MU+mu = V(M+m).................. Equation 1
⇒ Where:
M = mass of the first body m = mass of the second body U = Initial speed of the first body u = Initial speed of the second body V = common final speed .
From the question,
⇒ Given:
M = 0.24 kg U = 0.60 m/s m = 0.26 kg u = -0.20 m/s (traveling in opposite direction)
⇒ Substitute these values into equation 1
0.24(0.6)+0.26(-0.20) = V(0.24+0.2)
⇒ Solve for V
0.144-0.052 = 0.44V 0.44V = 0.092 V = 0.092/0.44 V = 0.209 V ≈ 0.21 m/s Hence the final speed of the combined masses is 0.21 m/s
Learn more about speed here: brainly.com/question/4931057
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