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2 years ago

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A wether forecaster reported that the total amount of rainfall for the month was 0.75 inch. He also reported that this amount wa

s 0.55 inch below the average amount of rainfall for the same month during the last ten years. What was the average amount of rainfall, in inches, for this month during the last ten years?

2 answers:

OverLord2011 [107]2 years ago

6 0

The prediction for average amount of rainfall for the for the month during last 10 years is given as

A weather forecaster reported that the total amount of rainfall for the month was 0.75 inch

The prediction for the same month this amount was 0.55 inch below the average amount of rainfall for the same month during the last ten years.

Summary table given by the forecaster =

Amount of rainfall for the month : 0.75 in.

Compared to average amount of rainfall for the month -0.55 in.

The average amount of rainfall , for this month during last ten years is to be determined

Let A be the average amount of rainfall for the month in the last ten years

The total amount of rainfall for the month = 0.75 inch

Given that this amount is 0.55 inch less than the average amount of rainfall for last 10 years hence we can write the Equation as formulated below

So the Average amount of rainfall for the for this month during last 10 years is given as

U 2 can help me by marking as brainliest.........

malfutka [58]2 years ago

5 0

Answer:

Yes, my answer is the same.

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Answer:

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regrine falcons frequently grab prey birds from the air. Sometimes they strike at high enough speeds that the force of the impac

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Answers:

a) 30 m/s

b) 480 N

Explanation:

The rest of the question is written below:

a. What is the final speed of the falcon and pigeon?

b. What is the average force on the pigeon during the impact?

<h3>a) Final speed</h3>

This part can be solved by the Conservation of linear momentum principle, which establishes the initial momentum $p_{i}$ before the collision must be equal to the final momentum $p_{f}$ after the collision:

$p_{i}=p_{f}$ (1)

Being:

$p_{i}=MV_{i}+mU_{i}$

$p_{f}=(M+m) V$

Where:

$M=480 g \frac{1 kg}{1000 g}=0.48 kg$ the mas of the peregrine falcon

$V_{i}=45 m/s$ the initial speed of the falcon

$m=240 g \frac{1 kg}{1000 g}=0.24 kg$ is the mass of the pigeon

$U_{i}=0 m/s$ the initial speed of the pigeon (at rest)

$V$ the final speed of the system falcon-pigeon

Then:

$MV_{i}+mU_{i}=(M+m) V$ (2)

Finding $V$ :

$V=\frac{MV_{i}}{M+m}$ (3)

$V=\frac{(0.48 kg)(45 m/s)}{0.48 kg+0.24 kg}$ (4)

$V=30 m/s$ (5) This is the final speed

<h3>b) Force on the pigeon</h3>

In this part we will use the following equation:

$F=\frac{\Delta p}{\Delta t}$ (6)

Where:

$F$ is the force exerted on the pigeon

$\Delta t=0.015 s$ is the time

$\Delta p$ is the pigeon's change in momentum

Then:

$\Delta p=p_{f}-p_{i}=mV-mU_{i}$ (7)

$\Delta p=mV$ (8) Since $U_{i}=0$

Substituting (8) in (6):

$F=\frac{mV}{\Delta t}$ (9)

$F=\frac{(0.24 kg)(30 m/s)}{0.015 s}$ (10)

Finally:

$F=480 N$

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