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Troyanec [42]
2 years ago
14

A wether forecaster reported that the total amount of rainfall for the month was 0.75 inch. He also reported that this amount wa

s 0.55 inch below the average amount of rainfall for the same month during the last ten years. What was the average amount of rainfall, in inches, for this month during the last ten years?​
Physics
2 answers:
OverLord2011 [107]2 years ago
6 0

The prediction for average amount of rainfall for the for the month during last 10 years is given as

 

A weather forecaster reported that the total amount of rainfall for the month was 0.75 inch

The prediction for the same month  this amount was 0.55  inch below the average amount of rainfall for the same month during the last ten years.

Summary table given by the forecaster =

Amount of rainfall for the month : 0.75 in.

Compared to average amount of rainfall for the month -0.55 in.

The average amount of rainfall , for this month during last ten years is to be determined

 

Let A be the average amount of rainfall for the month in the last ten years

The total amount of rainfall for the month = 0.75 inch

Given that this amount is 0.55 inch less than the average amount of rainfall for last 10 years hence we can write the Equation as formulated below

So the Average amount of rainfall for the for this month during last 10 years is given as

U 2 can help me by marking as brainliest.........

malfutka [58]2 years ago
5 0

Answer:

Yes, my answer is the same.

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The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
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This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

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Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

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Net force at A will be

FA' = √( NA² + FA²)

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we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

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FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

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FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

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