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3 years ago

10

18. The #2 on the diagram below represents what?

1 answer:

AveGali [126]3 years ago

3 0

Answer:

represents the fact that there is no diagram

Explanation:

it makes sense

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A charge of 11.748 nC is uniformly distributed along the x-axis from −2 m to 2 m . What is the electric potential (relative to z

svp [43]

Answer:

electric potential = 22.36 volt

Explanation:

given data

charge Q = 11.748 nC

distance d = 5 - 2 = 3 m

length = 2 + 2 = 4 m

Coulomb constant = 8.98755 × 109 N·m²/C ²

solution

electric potential is express as

electric potential = $\frac{Q}{4\pi \epsilon _o L}$ $ln(1+\frac{L}{d})$ ..............1

electric potential = $\frac{KQ}{L} ln(1+\frac{L}{d})$

put here value

electric potential = $\frac{8.98755\times 10^9\times 11.748\times 10{-9}}{4} ln(1+\frac{4}{3})$

electric potential = 22.36 volt

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3 years ago

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3 years ago

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The viscosity of all liquids decreases as the temperature is a) Increased b) decreased c) maintained constant d) fluctuating e)

mars1129 [50]

Answer:

b) decreased

Explanation:

Viscosity is the measure of the resistance between the layers of the liquid. On increasing temperature, the kinetic energy of the molecules of the liquid increases which in turn increase in the random motion of the molecules. Thus, the relative motion of the molecules in the liquid become easier and hence, viscosity decreases.

5 0

3 years ago

If aligned and continuous carbon fibers with a diameter of 9.90 micron are embedded within an epoxy, such that the bond strength

Zielflug [23.3K]

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3 years ago

Find the resultant of two forces 130 N and 110 N respectively, acting at an angle whose tangent

monitta

Answer:

$F_r = 200N$

Explanation:

Given

Let the two forces be

$F_1 = 130N$

$F_2 = 110N$

and

$\tan(\theta) = \frac{12}{5}$

Required

Determine the resultant force

Resultant force (Fr) is calculated using:

$F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)$

This means that we need to first calculate $\cos(\theta)$

Given that:

$\tan(\theta) = \frac{12}{5}$

In trigonometry:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

By comparing the above formula to $\tan(\theta) = \frac{12}{5}$

$Opposite = 12$

$Adjacent = 5$

The hypotenuse is calculated as thus:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 12^2 + 5^2$

$Hypotenuse^2 = 144 + 25$

$Hypotenuse^2 = 169$

$Hypotenuse = \sqrt{169$

$Hypotenuse = 13$

$\cos(\theta)$ is then calculated using:

$\cos(\theta)= \frac{Adjacent}{Hypotenuse}$

$\cos(\theta)= \frac{5}{13}$

Substitute values for $F_1$ , $F_2$ and $cos(\theta)$ in

$F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)$

$F_r^2 = 130^2 + 110^2 + 2*130*110*\frac{5}{13}$

$F_r^2 = 16900 + 12100 + 11000$

$F_r^2 = 40000$

Take square roots of both sides

$F_r = \sqrt{40000$

$F_r = 200N$

<em>Hence, the resultant force is 200N</em>

4 0

3 years ago