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makkiz [27]
3 years ago
12

what is the force of gravity attraction between an object with a mass of 0.5 kg and another object has a mass of 0.33 kg and a d

istance between Dam of 0.002 M ​
Physics
1 answer:
elena55 [62]3 years ago
4 0

Answer:

from \: newton \: law \: of \: gravitation \\ F =  \frac{GMm}{ {r}^{2} }  \\ G = 6.67 \times  {10}^{ - 11}  \\ M = 0.5 \: kg \\ m = 0.33 \: kg \\ r = 0.002 \: m \\ substitute \\ F =  \frac{(6.67 \times  {10}^{ - 11}) \times (0.5) \times (0.33)) }{ {(0.002)}^{2} }  \\  = 2.75 \times  {10}^{ - 6} N

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kati45 [8]

Answer:

velocity  = 472 m/s

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Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = \frac{\pi }{4} × (4.50×10^{-2})²  × velocity

solve it we get

velocity  = 472 m/s

and

when it 3 time diameter

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0.750 = \frac{\pi }{4} × 3 ×  (4.50×10^{-2})²  × velocity

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3 years ago
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Explanation:

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5 0
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A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated
Yakvenalex [24]

Answer:

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Explanation:

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3 0
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Answer:

a=4,32m/s^2

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alexandr1967 [171]

Answer:

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Explanation:

8 0
3 years ago
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