Solution :
a). Using Gauss's law :
, .........(1)
Let in equation (1)
Therefore, .............(2)
....................(3)
Therefore,
.............(4)
Now differentiating the equation (4) w.r.t. 'b', we get
Thus the radius for the inner cylinder conductor is
b). For the energy storage, substitute the radius in (4), we get
This is the amount of energy stored in the conductor.
The energy of the wave will decrease.
The energy of a wave is given as
E = h f
where E = energy of waver
h = plank's constant
f = frequency of the wave.
From the formula , we see that the energy of the wave is directly proportional to the frequency of the wave. hence as the frequency of the wave decrease, the energy of the wave will decrease.
Hope this helps. If you need clarification just ask me!
Answer:
Explanation:
It is a case of oscillation by simple pendulum . Expression for simple pendulum is given as follows
T =
where T is time period , l is length of pendulum and g is acceleration due to gravity .
, f is frequency of oscillation
For the given case
subsequently length becomes half so
dividing
f =
frequency of oscillation becomes √2 times.