Answer:
b) dm = ρab R dθ
c) m = ∫ ρab R dθ, from θ = 0 to θ = 2π
d) m = 2πρabR
Explanation:
b) We want to find the mass dm of a small chunk of the ring.
Mass is density times volume:
dm = ρ dV
Since a << R, we can approximate the volume as a rolled rectangular prism. Therefore, the volume of the chunk is the area of the cross section times the arc length.
dV = ab R dθ
dm = ρab R dθ
c) The mass of the entire ring is the sum of the masses of all the chunks.
m = ∫ dm
m = ∫ ρab R dθ, from θ = 0 to θ = 2π
d) ρ, a, b, and R are constants, so:
m = ρabR ∫ dθ
Evaluating the integral:
m = ρabR (θ|0 to 2π)
m = ρabR (2π − 0)
m = 2πρabR
Answer:
The speed of the car at the end of the 2nd second = 8.0 m/s
Explanation:
The equations of motion will be used to solve this problem.
A car starts from rest,
u = initial velocity of the car = 0 m/s
Accelerates at a constant rate in a straight line,
a = constant acceleration of the car = ?
In the first second the car moves a distance of 2.0 meters,
t = 1.0 s
x = distance covered = 2.0 m
x = ut + (1/2)at²
2 = 0 + (1/2)(a)(1²)
a = 4.0 m/s²
How fast will the car be moving at the end of the second second
Now,
a = 4.0 m/s²
u = initial velocity of the car at 0 seconds = 0 m/s
v = final velocity of the car at the end of the 2nd second = ?
t = 2.0 s
v = u + at
v = 0 + (4×2)
v = 8.0 m/s
The answer would be m1 = m2
FBD of m1 is the sum of the forces in the y direction =
0
0 = T - m1*g
transposing:
m1*g = T
FBD of m2 is the sum of the forces in the y direction = 0
0 = T - m2*g
transposing:
m2*g = T
set them equal to each other and solve for m1
m1*g = m2*g
= m1 = m2
Explanation:
The force on individual mass would be downwards or descending
and equal to the tension shaped by the other mass, which would be upward or
rising by the act of the seamless pulley, so the forces cancel on each mass.
We must rewrite the Newton's <span>Second</span> Law:
Applying in the question:
Answer: 6. 3 pairs of electron
Explanation:
A triple bond occurs when two atoms in a molecule shares 3 pairs of electron. A triple bond is also, a type of bond under the Covalent bond, which also includes, double bond and single bond.
Typically, a Covalent bond contains 2 elections. 1 from each atom. This means that, triple bond contains 6 electrons since there are three Covalent bonds, in a triple bond.
A triple bond is stronger than a single bond. It is characterized by sigma bonds between hybridized orbitals, and pi bonds between unhybridized p orbitals.
A triple bond is also vulnerable to "electron thieves". Example of compound with triple bond includes Dinitrogen, acetylene, carbon monoxide etc