A 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2 , what is t
he coefficient of kinetic friction between the box and the inclined plane?
1 answer:
Answer:
Explanation:
F = ma
mgsinθ - μmgcosθ = ma
gsinθ - μgcosθ = a
μgcosθ = gsinθ - a
μ = (gsinθ - a) / gcosθ
μ = (9.81sin24 - 0.245) / 9.81cos24
μ = 0.4178906...
μ = 0.418
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