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HACTEHA [7]
3 years ago
14

A ball is launched as a projectile with initial speed v at an angle θ above the horizontal. using conservation of energy, find

the maximum height hmax of the ball's flight. express your answer in terms of v, g, and θθ.
Physics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

Explanation:

I will us θ as the angle above horizontal as I don't know how to make your chosen symbol for angle.

           KEy = PE

½m(vsinθ)² = mgh

                h = (vsinθ)²/2g

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