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HACTEHA [7]
3 years ago
14

A ball is launched as a projectile with initial speed v at an angle θ above the horizontal. using conservation of energy, find

the maximum height hmax of the ball's flight. express your answer in terms of v, g, and θθ.
Physics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

Explanation:

I will us θ as the angle above horizontal as I don't know how to make your chosen symbol for angle.

           KEy = PE

½m(vsinθ)² = mgh

                h = (vsinθ)²/2g

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Answer:

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Explanation:

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A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the va
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A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
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Answer:

T=66262.4s

Explanation:

From the question we are told that:

Altitude A=2.90 *10^7

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V=(\frac{GM}{d} )^{0.5}

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Therefore

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4 0
3 years ago
A tennis ball is dropped from 1.16 m above the
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Answer:

Vf = 4.77 m/s

Explanation:

During the downward motion we can easily find the final velocity or the velocity with which the ball hits the ground, by using third equation of motion. The third equation of motion is given as follows:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height = 1.16 m

Vf = Final Velocity of Ball = ?

Vi = Initial Velocity of Ball = 0 m/s (Since, ball was initially at rest)

Therefore, using these values in the equation, we get:

(2)(9.8 m/s²)(1.16 m) = Vf² - (0 m/s)²

Vf = √(22.736 m²/s²)

<u>Vf = 4.77 m/s</u>

6 0
3 years ago
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