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blsea [12.9K]
2 years ago
13

7. 13 a turbine receives steam at 6 mpa, 600°c with an exit pressure of 600 kpa. Assume the turbine is adiabatic and neglect kin

etic energies. Find the exit temperature and the specific work
Physics
1 answer:
AnnyKZ [126]2 years ago
6 0

The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.

<h3 /><h3>What is temperature?</h3>

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

If the given turbine is assumed to be reversible;

\rm P_I(Initial pressure)=60 mpa = 60 bar

\rm  T_i(Initial temperature)=600° C

\rm P_e (Exit pressure)=600 kpa=6 bar

The heat balance equation is;

\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e

The change in the entropy is;

\rm S_2-S_1=\frac{\delta q}{dt}

The work done by the turbine is;

\rm W_t = h_i-h_e\\\\ W_t =3658.4 -29.5019\\\\  W_t =708.2 \ kJ/kg

Hence,the work done by the turbine will be 708.2 kJ/kg.

To learn more about the temperature, refer to the link;

brainly.com/question/7510619

#SPJ4

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Vocabulary word for the total amount of charge in a closed system remains constant
Usimov [2.4K]

Answer:

i think this is it i dont know tho A conservation law stating that the total electric charge of a closed system remains constant over time, regardless of other possible changes within the system. "Conservation of charge." YourDictionary. LoveToKnow

7 0
3 years ago
Mary and her younger brother Alex decide to ride the 17-foot-diameter carousel at the State Fair. Mary sits on one of the horses
lorasvet [3.4K]

Answer:

\omege_A=\omega_M

v_M=1.6v_A

Explanation:

A denotes Alex

M denotes Mary

r = Distance from center

Mary and Alex will have the equal displacements in equal interval of time as they are in uniform circular motion. So,

\omega_A=\omega_M

Tangential speed speed is given by

\dfrac{v_M}{v_A}=\dfrac{r_M\omega_M}{r_A\omega_A}\\\Rightarrow \dfrac{v_M}{v_A}=\dfrac{r_M}{r_A}\\\Rightarrow \dfrac{v_M}{v_A}=\dfrac{8}{5}\\\Rightarrow \dfrac{v_M}{v_A}=1.6\\\Rightarrow v_M=1.6v_A

The tangential speed of Mary is v_M=1.6v_A

5 0
4 years ago
Two disks of polaroid are aligned so that they polarize light in the same plane. Calculate the angle through which one sheet nee
Olegator [25]

Answer: The unpolarized light's intensity is reduced by the factor of two when it passes through the polaroid and becomes linearly polarized in the plane of the Polaroid. When the polarized light passes through the polaroid with the plane of polarization at an angle \theta with respect to the polarization plane of the incoming light, the light's intensity is reduced by the factor of \cos^2\theta (this is the Law of Malus).

Explanation: Let us say we have a beam of unpolarized light of intensity I_0 that passes through two parallel Polaroid discs with the angle of \theta between their planes of polarization. We are asked to find \theta such that the intensity of the outgoing beam is I_2. To solve this we follow the steps below:

Step 1. It is known that when the unpolarized light passes through a polaroid its intensity is reduced by the factor of two, meaning that the intensity of the beam passing through the first polaroid is

I_1=\frac{I_0}{2}.

This beam also becomes polarized in the plane of the first polaroid.

Step 2. Now the polarized beam hits the surface of the second polaroid whose polarization plane is at an angle \theta with respect to the plane of the polarization of the beam. After passing through the polaroid, the beam remains polarized but in the plane of the second polaroid and its intensity is reduced, according to the Law of Malus, by the factor of \cos^2\theta. This yields I_2=I_1\cos^2\theta. Substituting from the previous step we get

I_2=\frac{I_0}{2}\cos^2\theta

yielding

\frac{2I_2}{I_0}=\cos^2\theta

and finally,

\theta=\arccos\sqrt{\frac{2I_2}{I_0}}

3 0
3 years ago
It takes 50.0 J to push a large box 4.00 m across a floor. Assuming the push is in the same direction as the move, what is the m
Blababa [14]
<h3><u>Answer;</u></h3>

12.5 Newtons

<h3><u>Explanation;</u></h3>

Work done is defined as the product of force and distance covered or moved. It is measured in joules.

Work done = Force × distance

Therefore; making force the subject;

Force = work done/distance

         = 50.0 J/ 4.00 m

         =<u> 12.5 Newtons.</u>

8 0
3 years ago
During photosynthesis *
Lady_Fox [76]

Answer:

<em>converted</em>

Explanation:

into chemical

4 0
3 years ago
Read 2 more answers
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