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Pie
2 years ago
10

What is the equation of the line that is parallel to the line 12x + 15y = 10 and passes through the point (5, −2)

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
7 0

Answer:

The slope of the given line and a line parallel to it is 5/2.

Step-by-step explanation:

Explanation:

Given:

5

x

−

2

y

=

11

is the standard form of a linear equation.

A line parallel to this line has the same slope. To determine the slope, solve for

y

to change the equation to slope-intercept form:

y=mx+b, where: m is the slope and b is they intercept.5x−2y=11      

Subtract 5x from both sides. −2y=−5x+11

Divide both sides by −2. y=−5/−2x+11/2

Simplify. y=5/2 x −11/2

The slope of the given line and a line parallel to it is 5/2.

.

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3 years ago
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Read 2 more answers
Laura is 12 years old witch 6/7 of her brothers age how old is her brother
sweet [91]

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3 0
3 years ago
Plssssss help fast!!!!Launching From a Tower
aleksandrvk [35]

Answer:

A. h = 64

B.  t = 4 -> 4 seconds

C. t = 1.5 -> 1.5 seconds

D. maximum height is 100 ft

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

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t = 4 or t = -1

Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.

C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

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2 years ago
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