a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground
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The conservation of energy and Newton's second law allows us to find the results about Jason's falling motion are;
- The energy when reaching the water is K = 13720 J
- The average force of the water to stop it is: F = 2744 N
The conservation of energy is one of the most important principles of physics, stable that if there is no friction force, mechanical energy is conserved at all points.
Mechanical energy is the sum of kinetic energy plus potential energy.
Let's look for the energy at two points
Starting point. Get higher.
Em₀ = U = 13720 J
Final point. Lower down.
= K
Friction in the air is negligible, so energy is conserved.
K = 13720J
<h3>Kinematics and Newton's law.</h3><h3> </h3>
They indicate that it stops 5m under the water, if we assume that the water acts with a constant force, we can use kinematics and Newton's second law to find this force.
The kinematics expression to find the acceleration is
v² =v₀² – 2ay
When it stops the speed is zero.
Newton's second law is:
F = ma
F = m ( )
The expression for the kinetic energy is:
K = ½ m v₀²
Let's substitute.
F =
Let's calculate.
F=
F = 2744N
In conclusion using conservation of energy and Newton's second law we can find the results about Jason's falling motion are;
- The energy when reaching the water is K = 13720 J
- The average force of the water to stop it is: F = 2744 N
Learn more about energy here: brainly.com/question/14274074