Officials in the House of Representives have are able to serve a 2 year term and there are no limits as to how many terms.
Answer:
C. a disturbance that travels through a medium with a transfer of energy and without a transfer of matter
Explanation:
A wave is any disturbance that transfers energy from one location to the other via a substance called medium. It is important to note that a wave only conveys energy and not matter. For example, sound wave is a type of wave that carries sound energy from one place to another via mediums such as water, air etc.
Hence, according to this question, a wave can be described as a disturbance that travels through a medium with a transfer of energy and WITHOUT A TRANSFER OF MATTER.
The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.
The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.
<h3>What is a Circuit ?</h3>
In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.
- The directional valve shifts, causing the actuator to move faster than pump flow can fill it due to an overrunning load. Oil is leaking from one side, whereas there is none on the other.
Hence, flow control circuit design that can best control an overrunning load is the opposing circuit
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From the diagram we have that
Therefore the direction is 30° from east of south
Answer:
v₁ = 2.48m/s, v₂ = 0.02m/s
Explanation:
Momentum p must be conserved. p = mv
1) First person throwing the snow ball. The momentum before the throw:
p = (65kg + 0.045kg) * 2.5 m/s
The momentum after the throw:
p = 65kg * v₁ + 0.045kg * 30m/s
Solving for the velocity v₁ of person 1:
v₁ = ((65kg + 0.045kg) * 2.5 m/s - 0.045kg * 30m/s) / 65kg = 2.48m/s
2) Second person catching the ball. The momentum before the catch:
p = 0.045kg * 30m/s + 60kg * 0m/s
The momentum after the catch:
p = (60kg + 0.045kg) * v₂
Solving for velocity v₂ of person 2:
v₂ = 0.045kg * 30m/s / (60kg + 0.045kg) = 0.02 m/s
