3 years ago

Which way should a ceiling fan rotate in the summer

2 answers:

6 0

During summer months, your ceiling fan blades should be set to spin counterclockwise. When your ceiling fan spins quickly in this direction, it pushes air down and creates a cool breeze.

Luba_88 [7]3 years ago

5 0

Summertime counter clockwise

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A straight vertical wire carries a current of 1.0 A into the page in a region where the magnetic field strength is 0.60 T. What

Advocard [28]

Answer:

force on the wire of section cm will be $6\times 10^{-3}N$

Direction of force on the wire will be in south direction

Explanation:

We have given current in the wire i = 1 A

Magnetic field strength B = 0.6 T

We have to find the force on 1 cm section of the wire so l = 1 cm = 0.01 m

Force on the wire containing current is equal to

$F=iBL$

$F=1\times 0.6\times 0.01=6\times 10^{-3}N$

So force on the wire of section cm will be $6\times 10^{-3}N$

Direction of force on the wire will be in south direction

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3 years ago

Exercising in hot weather can cause what side effects ?

trapecia [35]

Answer:

dehydration, lots of sweating, heat stroke, heat exhaustion: nausea, dizziness, vomitting, diahreaa, headache

Explanation:

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3 years ago

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A question is scientific if you can answer it using which of the following?

pav-90 [236]

C. Observations and measurements

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3 years ago

your softball coach needs to add a new player to the team roster. which of these people would most likely demonstrate the best s

Shkiper50 [21]

It would be easier to answer your question if you attached options. Anyway I remember that the right answer to that question is:<span> marissa, because she has cheered for the team all season long</span>

6 0

3 years ago

The resistivity of gold is 2.44 x 10-8 ohms.m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries

harkovskaia [24]

Answer:

E=0.036 V/m

Explanation:

Given that

Resistivity ,ρ=2.44 x 10⁻⁸ ohms.m

d= 0.9 mm

L= 14 cm

I = 940 m A = 0.94 A

We know that electric field E

E= V/L

V= I R

R=ρL/A

So we can say that

E= ρI/A

Now by putting the values

$E=\dfrac{ 2.44\times 10^{-8}\times 0.94}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}$

E=0.036 V/m

6 0

3 years ago