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3 years ago

Which way should a ceiling fan rotate in the summer

2 answers:

6 0

During summer months, your ceiling fan blades should be set to spin counterclockwise. When your ceiling fan spins quickly in this direction, it pushes air down and creates a cool breeze.

Luba_88 [7]3 years ago

5 0

Summertime counter clockwise

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A 6.30 kg piece of solid copper metal at an initial temperature T is placed with 2.00 kg of ice that is initially at -16.0 ∘C. T

Viktor [21]

Answer:

179 degree

Explanation:

Solid copper will lose heat to warm up and melt ice . Since all the ice has not melted so final temperature of mixture will be zero.

heat gained by ice to reach temperature of zero degree

= mass of ice x specific heat of ice x rise of temp

= 2 x 2093 x 16 = 66976 J

Heat gained to melt 1.1. kg of ice

mass x latent heat of ice

1.1 x 334000

= 367400

total heat

= 367400 + 66976

=434376

Heat lost by copper

= 6.3 x 385 x T

where 385 is specific heat of copper and T is initial temperature

heat lost = heat gained

6.3 x 385 T = 434376

T = 434376 / (6.3 x 385)

= 179 degree .

3 0

3 years ago

The suspended load of a stream _____.

denis23 [38]

the first one ( usually consists of fine sand, silt, and clay particles )

Hope im right!(:

4 0

3 years ago

Read 2 more answers

What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s 2 ) towards the Eart

Wittaler [7]

Answer:

The centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ is $1.020x10^{-3}m/s^{2}$

Explanation:

The centripetal acceleration is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude $71.9^{\circ}$ . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

$\cos \theta = \frac{adjacent}{hypotenuse}$

$\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}}$ (3)

Where $r_{71.9^{\circ}}$ is the radius at the latitude of $71.9^{\circ}$ and $r_{e}$ is the radius at the equator ( $6.37x10^{6}m$ ).

$r_{71.9^{\circ}}$ can be isolated from equation 3:

$r_{71.9^{\circ}} = r_{e} \cos \theta$ (4)

$r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})$

$r_{71.9^{\circ}} = 1.97x10^{6} m$

Then, equation 2 can be used

$v = \frac{2 \pi (1.97x10^{6} m)}{24h}$

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

$T = 24h . \frac{3600s}{1h}$ ⇒ $84600s$

$v = \frac{2 \pi (1.97x10^{6} m)}{84600s}$

$v = 146.31m/s$

Finally, equation 1 can be used:

$a = \frac{(146.31m/s)^{2}}{(1.97x10^{6}m)}$

$a = 0.010m/s^{2}$

Hence, the centripetal acceleration is $0.010m/s^{2}$

To given the centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ it is gotten:

$\frac{0.010m/s^{2}}{9.8 m/s^{2}} = 1.020x10^{-3}m/s^{2}$

6 0

3 years ago

A 0.140-kg baseball is dropped from rest from a height of 1.8 m above the ground. It rebounds to a height of 1.4 m. What change

aliina [53]

Answer:

$\Delta p=-1.56\ kg-m/s$

Explanation:

It is given that,

Mass of the baseball, m = 0.14 kg

It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :

$u=\sqrt{2gh}$

h = 1.8 m

$u=\sqrt{2\times 9.8\times 1.8}$

u = 5.93 m/s

Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :

$v=\sqrt{2gh'}$

h' = 1.4 m

$v=-\sqrt{2\times 9.8\times 1.4}$

v = -5.23 m/s

The change in the momentum of the ball is given by :

$\Delta p=m(v-u)$

$\Delta p=0.14(-5.23-5.93)$

$\Delta p=-1.56\ kg-m/s$

So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.

4 0

4 years ago

When acceptance and love are given to another only when certain expectations or standards are met, __________ is being demonstra

Anna71 [15]

Answer:

conditional positive regard

Explanation:

Condition Positive Regard can be described as a situation in which positivity, love or affection are only given when certain criteria or demands are met. Whereas on the contrary, an unconditional positive regard occurs when a person is loved without any demands or criteria.

Condition positive regards means to love or show affection for someone or something depending on its values in our eyes.

7 0

3 years ago