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Zielflug [23.3K]
3 years ago
13

I need help with answering the given question.

Physics
1 answer:
Viktor [21]3 years ago
8 0
The two hydrogen gas molecules split and the two oxygen gas molecules split and made two water molecules by having two hydrogen gas molecules and one oxygen gas molecule join twice... 
Therefore, there would be 3 or 6
if i am not mistaken
hope it helps
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A wavelength is a measure of distance between two consecutive crests or trough. So , the unit of wavelength is same as unit of distance. I.e metre

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A ray of light (f = 5.09 x 1014 Hz) is incident on the boundary between air and an unknown material X at an angle of incidence o
11Alexandr11 [23.1K]

Answer:

A) Material X is flint glass

B) Speed of light in the X material is 1.807 x 10^{8} m/s

C) Angle of refraction of light in medium X is 29.57^{o}

Explanation:

Given data:

frequency of the light f = 5.09 x 10^{14} Hz

angle of incidence Θ_{i} = 55^{o}

index of refraction of material n_{2} = 1.66

A) To find material X

Given the index of refraction is 1.66 and hence the material is the flint glass

B) To calculate the speed of light in the material.

We know that the relation between index of refraction (n), velocity of light (c = 3 x 10^{8} m/s) and velocity of light is given by the equation:

n = c/v

Hence,

Speed of light in the X material v = c/n

                                                          = \frac{3 x 10^{8} }{1.66}

                                                          = 1.807 x 10^{8} m/s

C) To calculate angle of refraction of light in medium X

We know that the Snell's law states that

                       n_{1} sin Θ_{i}  = n_{2} sin Θ_{r}

n_{1} = incident index

n_{2}  = refracted index

Θ_{i} = incident angle

Θ_{r} = refracted angle

In given problem, n_{1} = 1 since medium is air

Substituting the known values, we get

1 x  sin 55^{o}  = 1.66 x sin Θ_{r}

sin Θ_{r} = sin 55^{o} /1.66

           = 0.4935

Hence, angle of refraction of light in medium X Θ_{r} = sin^{-1} (0.4935)

                                                                                       = 29.57^{o}

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How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
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<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

  • Initial Velocity of car = 44km / hr.
  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

  • v is final Velocity.
  • u is Initial velocity.
  • a is acceleration.
  • t is time taken.

Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

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