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yaroslaw [1]
3 years ago
8

Un objeto que es empujado sobre una superficie plana, tiene una masa de 80 kg y dicha fuerza tiene un valor de 300 N. Calcule la

fuerza Normal y la fuerza de Fricción para que este en equilibrio. A. Ff=300 N N=784.8 N B. Ff=300 N N=780 N C. Ff=200 N N=750 N AYUDENME POR FA LA NECESITO
Physics
1 answer:
Gennadij [26K]3 years ago
3 0

Responder:

A. Ff = 300 N N = 784,8 N

Explicación:

Dado

Masa del cuerpo = 80 kg

Fuerza de movimiento Fm = 300N

Dado que el cuerpo no está acelerando, la fuerza de fricción (Ff) es igual a la fuerza de movimiento que actúa sobre el cuerpo, ya que la fuerza de fricción es una fuerza de oposición, es decir, Fm = Ff

Dado que Fm = 300N, Ff = 300N

La reacción normal que actúa en el cuerpo es igual al peso.

N = W = mg

g es la aceleración debida a la gravedad

g = 9,8 m / s

N = mg

N = 80 (9,81)

N = 784,8N

Por tanto, la fuerza normal que actúa sobre el cuerpo es 784,8 N

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