A spring that has a spring constant of 440 N/m exerts a force of 88 N on a box. What is the displacement of the spring? 0. 2 m 5

Question

2 years ago

15

m 352 m 528 m.

1 answer:

mina [271] · Answer 1 · 2023-02-02T10:47:57+03:00

The displacement of a spring is directly proportional to the applied force. The displacement of the given spring is 50.45 m.

<h2></h2><h2>From Hooke's law:</h2>

$F = kx$

Where,

$F$ - force applied = 88 N

$k$ - spring constant = 440 N/m

$x$ - displacement = ?

Put the values in the formula,

$88 = 440 \times x\\\\x = \dfrac {440 }{88}\\\\x = 50.45 \rm \ m$

Therefore, the displacement of the given spring is 50.45 m.

Learn more about Hooke's law: