Here try this. The pic is the answer
The spring is neither stretched nor compressed. an object having a mass m is attached to the free end of the spring. consider an action
Answer:
1408.685 KN/C
Explanation:
Given:
R = 0.45 m
σ = 175 μC/m²
P is located a distance a = 0.75 m
k = 8.99*10^9
- The Electric Field Strength E of a uniformly solid disk of charge at distance a perpendicular to disk is given by:

part a)
Electric Field strength at point P: a = 0.75 m

part b)
Since, R >> a, we can approximate a / R = 0 ,
Hence, E simplified relation becomes:

E = σ / 2*e_o
part c)
Since, a >> R, we can approximate. that the uniform disc of charge becomes a single point charge:
Electric Field strength due to point charge is:
E = k*δ*pi*R^2 / a^2
Since, R << a, Surface area = δ*pi
Hence,
E = (k*δ*pi/a^2)
Answer:
just guys
Explanation:
and if not i need how old you are sorry just trying to be safe
Answer:
The inner planets are less dense than the outer planets
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