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Volgvan
3 years ago
8

Which of the following statements is an example of absolute time?

Physics
2 answers:
Nataly_w [17]3 years ago
7 0
I think the answer is : Bobby exactly three years old today

to put it simply, absolute time can be perceived without depended to other object as comparison.

for example Evan is older than james is not an absolute time, because this conditions depend on the age comparison between the two subject

ExtremeBDS [4]3 years ago
7 0

The answer is B, Bobby is exactly three years old today

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LiRa [457]

Answer:

A magnetic field line can never cross another field line. The magnetic field is unique at every point in space. Magnetic field lines are continuous and unbroken, forming closed loops. Magnetic field lines are defined to begin on the north pole of a magnet and terminate on the south pole.

Explanation:

3 0
3 years ago
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A 300 g wooden block on a smooth, level surface is firmly attached to a very light horizontal spring with a spring constant of 2
Tom [10]

the solution for the oscillatory movement allows to find the result for the amplitude of the initial displacement is:

  • The range of motion is: A = 4.44 cm

<h3>Oscillatory movement.</h3>

The oscillatory periodic motion of a system occurs when there is a recovered force, in the special case that this force is proportional to the displacement is called simple harmonic motion, which is described by the expression.

            x = A cos (wt + Ф)

            w² = k/m

where x is the displacement, A the amplitude, w the angular velocity, t the time, k the spring constant, m the mass, and Ф a phase constant determined by the initial conditions.

Let's find the angular velocity/

            w= \sqrt{ \frac{200}{0.300} }

            w = 25.8 rad/s

Let's look for the constant Ф, as the system is released from rest its initial velocity is zero, for zero time. The definition of speed is:

             v= \frac{dx}{dt}

             v= - A w sin (wt +Ф)

             

             0 = -A w sin Ф

            Ф= 0

They indicate that at a given instant of the time the velocity is v= 50.0 cm/s and it is in a position x= 4.00 cm, let us write the equations for this time

Position.

               4.00 = A cos 25.8t

Speed.

              50.0 = - At 25.8 sin 25.8t

To solve the system, ;et's square and add.

              Cos² 25.8t = \frac{16}{A^2}

              sin² 25.8t = \frac{3.756}{A^2 }

              1 = \frac{1}{A^2} \ (16 + 3.756)

               A = \sqrt{19.756}

               A= 4.44 cm

In conclusion using the solution for the oscillatory movement we can find the result for the amplitude of the initial displacement is:

The range of motion is: A = 444 cm

Learn more about oscillatory motion here:  brainly.com/question/14311816

4 0
2 years ago
A chief finds a glittering stone which he shows to the family. The family assures him that the stone is pure gold but he doubts.
Nina [5.8K]

I will tell the Chief about the high worth of the Gold and the various

substances it can be used to produce.

<h3>What is Gold?</h3>

Gold is a naturally occurring element with a bright, slightly orange yellow

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substances such as:

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The Chief should however be told about the high worth value of Gold and

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5 0
3 years ago
Polarizers #1 and #3 are "crossed" such that their transmission axes are perpendicular to each other. Polarizer #2 is placed bet
Tomtit [17]

Answer:

Explanation:

The angle between the polariser 1 and 2 is 60°

If I₁ be the intensity of light after polariser 1 , its intensity after polariser 2 that is I₂ can be expressed as follows

I₂ = I₁ cos² 60

= I₁ x 1/4

=  I₁ x \frac{1}{4}

3 0
3 years ago
A heavy boy and a lightweight girl are balanced on a massless seesaw. The boy moves backward, increasing his distance from the p
slava [35]

Answer:

b. The side the boy is sitting on will tilt downward

Explanation:

Initially, the seesaw is balanced because the torque exerted by the boy is equal to the torque exerted by the girl:

\tau_b = \tau_g\\W_b d_b = W_g d_g

where

Wb is the weight of the boy

db is the distance of the boy from the pivot

Wg is the weight of the girl

dg is the distance of the girl from the pivot

When the boy moves backward, the distance of the boy from the pivot ((d_b) increases, therefore the torques are no longer balanced: the torque exerted by the boy will be larger, and therefore the side of the boy will tilt downward.

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