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Volgvan
2 years ago
8

Which of the following statements is an example of absolute time?

Physics
2 answers:
Nataly_w [17]2 years ago
7 0
I think the answer is : Bobby exactly three years old today

to put it simply, absolute time can be perceived without depended to other object as comparison.

for example Evan is older than james is not an absolute time, because this conditions depend on the age comparison between the two subject

ExtremeBDS [4]2 years ago
7 0

The answer is B, Bobby is exactly three years old today

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Solution A has a specific heat of 2.0 J/g◦C. Solution B has a specific heat of 3.8 J/g◦C. If equal masses of both solutions start
fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

<em>We have a formula for such condition,</em>

Q=m.c.\Delta T.....................................(1)

where:

  • \Delta T= temperature difference
  • Q= heat energy
  • m= mass of the body
  • c= specific heat of the body

<u>Proving mathematically:</u>

<em>According to the given conditions</em>

  • we have equal masses of two solutions A & B, i.e. m_A=m_B
  • equal heat is supplied to both the solutions, i.e. Q_A=Q_B
  • specific heat of solution A, c_{A}=2.0 J.g^{-1} .\degree C^{-1}
  • specific heat of solution B, c_{B}=3.8 J.g^{-1} .\degree C^{-1}
  • \Delta T_A & \Delta T_B are the change in temperatures of the respective solutions.

Now, putting the above values

Q_A=Q_B

m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1

Which proves that solution A attains a higher temperature than solution B.

7 0
3 years ago
A gymnast with mass m1 = 43 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 =
Liula [17]
<span>A gymnast with mass m1 = 43 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 = 115 kg and length L = 5 m. Each support is 1/3 of the way from each end. Initially the gymnast stands at the left end of the beam. 
1)What is the force the left support exerts on the beam? 
2)What is the force the right support exerts on the beam? 
3)How much extra mass could the gymnast hold before the beam begins to tip? 
Now the gymnast (not holding any additional mass) walks directly above the right support. 

4)What is the force the left support exerts on the beam? 
5)What is the force the right support exerts on the beam?</span>
6 0
3 years ago
(b) Which has more mass: 50 cm of gold or 50 cm of aluminum? Explain.
monitta
Gold’s molar mass is about 196 while aluminum is about 27, thus 50cm of gold has more mass
8 0
2 years ago
EX
Serjik [45]

Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.

<h3>What is the average speed of the train?</h3>

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

  • Distance traveled = 221miles
  • Elapsed time = 3 hours and 40 minutes

First we convert miles to meters and Hours minutes to seconds.

221 miles = ( 221 × 1609.344 )m = 355665.024 meters

3 hours and 40 minutes = ( 3×60×60)s + ( 40×60)s

= 10800s + 2400s

= 13200s

Now, determine the average speed.

Speed = Distance ÷ time

Speed = 355665.024m / 13200s

Speed = 26.944m/s

Given the distance traveled and time elapsed, the average speed of the train is approximately 26.944m/s.

Learn more about speed here: brainly.com/question/7359669

#SPJ1

4 0
1 year ago
If the volume of a sample of gas is reduced at constant temperature, the average velocity of the molecules _______, the average
VLD [36.1K]

Answer:

Explanation:

If the volume of a sample of gas is reduced at constant temperature, the average velocity of the molecules increases, the average force of an individual collision increases, and the average number of collisions with the wall, per unit area, per second increases.

As volume is reduced, the gas molecules come closer together, which increases the number of collisions between them and their collisions with the container walls. Also, since the distance traveled by each molecule between successive collision decreases, the molecule velocity doesn't decrease much within collisions as a result of which, the average velocity is higher compared to when the gas is stored in a larger volume. Finally, due to constant collisions, the direction of molecule travel changes rapidly owing to which the acceleration of molecules increases.

6 0
3 years ago
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