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2 years ago

Pls Due today pls help asfast as possible

Chemistry

1 answer:

Stels [109]2 years ago

5 0

Answer: D. 10,000 km = Exosphere; 690 km = Thermosphere; 85 km Mesosphere; 50 km = Stratosphere; 20 km = Troposphere

2. True

3. True

4. True

5. True

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3. what is the relationship between a coefficient; chemical formula

Novosadov [1.4K]

The coefficient in a chemical formula represents the amount of each chemical present. The amount of a substance is measured in moles.

4 0

2 years ago

What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperatu

tatyana61 [14]

Answer:

1) 6.0 atm.

2) 2.066 atm.

Explanation:

From the general law of ideal gases:

PV = nRT.

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

1) What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 2.0 atm and the temperature is held constant?

At constant T and at two different (P, and V):

P₁V₁ = P₂V₂.

P₁ = 2.0 atm, V₁ = 150.0 mL.

P₂ = ??? atm, V₂ = 50.0 mL.

∴ P₂ = P₁V₁/V₂ = (2.0 atm)(150.0 mL)/(50.0 mL) = 6.0 atm.

2. A sample of a gas in a rigid container at 30.0°C and 2.00 atm has its temperature increased to 40.0°C. What will be the new pressure?

Since the container is rigid, so it has constant V.

At constant V and at two different (P, and T):

P₁/T₁ = P₂/T₂.

P₁ = 2.0 atm, T₁ = 30.0°C + 273 = 303 K.

P₂ = ??? atm, T₂ = 40.0°C + 273 = 313 K.

∴ P₂ = P₁T₂/T₁ = (2.0 atm)(313.0 K)/(303.0 K) = 2.066 atm.

3 0

3 years ago

Convert 23.064 mass to mg

Ierofanga [76]

ANSWER: 23064 mg

EXPLANATION: To convert grams to milligrams, we multiply by 1000.

23.064 g x 1000 = 23064 mg

3 0

3 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

3 years ago

Which of the following locations would experience the highest rate of sublimation?

g100num [7]

I think its the arctic ice caps

6 0

3 years ago

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