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ASHA 777 [7]
2 years ago
9

Pls Due today pls help asfast as possible

Chemistry
1 answer:
Stels [109]2 years ago
5 0

Answer: D. 10,000 km = Exosphere; 690 km = Thermosphere; 85 km Mesosphere; 50 km = Stratosphere; 20 km = Troposphere

2. True

3. True

4. True

5. True

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Discuss Newland octave law and it's rejection
Delvig [45]
It's where chemical elements are organized based on atomic weight. Also, like/similar physical and chemical properties in each interval of 7 elements. 
It was a silly reason it was rejected. It was rejected because it's octaves were too similar to those in music.
I hope this helps!
7 0
3 years ago
A gray whale can travelan average of 120<br> km per day as it migrates.
masha68 [24]

Explanation:

False, gray whales average 75 miles per day at a speed of 5 mph and is the longest annual migration of any mammal.

8 0
3 years ago
Read 2 more answers
At what temperature would 2.10moles of N2 gas have a pressure of 1.25atm and fill a 25.0 L tank
hodyreva [135]

Answer:

\large \boxed{\text{-92 $^{\circ}$C}}

Explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT

Data  

p = 1.25 atm

V = 25.0 L

n = 2.10 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculations

1. Temperature in kelvins

\begin{array} {rcl}pV & = & nRT\\\text{1.25 atm} \times \text{25.0 L} & = & \rm\text{2.10 mol} \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times T\\31.25&=&0.09847T\text{ K}^{-1}\\T& = &\dfrac{31.25}{\text{0.098 47 K}^{-1}}\\\\& = &\text{181 K}\end{array}

2. Temperature in degrees Celsius

\begin{array} {rcl}T & = & (181 - 273.15) \, ^{\circ}\text{C}\\& = & -92 \, ^{\circ}\text{C}\\\end{array}\\\text{The temperature of the gas is $\large \boxed{\mathbf{-92 \, ^{\circ}}\textbf{C}}$}

8 0
3 years ago
Column A 1. Reproduction: Reproduction 2. offspring: offspring 3. gamete: gamete 4. Budding: Budding 5. Binary fission: Binary f
7nadin3 [17]

Answer:

1. Reproduction: One or two parents, organisms make new offspring

2. Offspring: A new living organism

3. Gamete: female and male create mini-me by cell division

4. Budding: Hydra

5. Binary fission: Bacteria

6. Zygote: The original cell after egg cell and sperm cell join

7. Fragmentation/Regeneration: Sea star / Planarian

8. Mitosis: Healling and growth occurs in budding

9. Meiosis: Egg or sperm cell/ specialized cells

Explanation:

1. Reproduction is the process by which organisms make new offspring either sexually (involving two parents) or asexually (involving one parent only).

2. An Offspring is a new living organism

3. A gamete is a mature sexual reproductive cell, as a sperm or egg, that unites with another cell to form a new organism. It formed from female and male parents by cell division known as meiosis

4. Budding is a form of asexual reproduction in which a new offspring grows out from a part of the parent. It occurs in Hydra.

5. Biinary fission is a form of asexual reproduction which involves a separation of the parent into two new offspring. It commonly occurs in Bacteria

6. Zygote is the original cell formed after egg cell and sperm cell fuse.

7. Fragmentation/Regeneration: this is a form of reproduction in which a parent splits into fragments which are then able to develop into new organisms. It occurs in Sea star and Planarians

8. Mitosis is a form of cell division which a cell divides into two identical daughter cells with the same genetic components as the parent cell. It functions in healing and growth as well as in budding

9. Meiosis is a type of cell division that results in the production of sex cells or gametes. The number of chromosomes in the parent cell is halved and four gamete cells are produced. Egg or sperm cell/ specialized cells are produced by meiosis.

5 0
3 years ago
Consider the insoluble compound nickel(II) hydroxide , Ni(OH)2 . The nickel ion also forms a complex with cyanide ions . Write a
natali 33 [55]

Answer: Equilibrium constant for this reaction is 2.8 \times 10^{15}.

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)

We know that,

      K = K_{f} \times K_{sp}

We are given that, K_{f} = 1.0 \times 10^{31}

and,    K_{sp} = 2.8 \times 10^{-16}

Hence, we will calculate the value of K as follows.

     K = K_{f} \times K_{sp}

     K = (1.0 \times 10^{31}) \times (2.8 \times 10^{-16})

        = 2.8 \times 10^{15}

Thus, we can conclude that equilibrium constant for this reaction is 2.8 \times 10^{15}.

4 0
2 years ago
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