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2 years ago

Explain how a mixed solution of ethanoic acid and sodium ethanoate would be a suitable

Chemistry

1 answer:

Nadusha1986 [10]2 years ago

6 0

Answer:

Acidic buffer solutions are commonly made from a weak acid and one of its salts - often a sodium salt. A common example would be a mixture of ethanoic acid and sodium ethanoate in solution. In this case, if the solution contained equal molar concentrations of both the acid and the salt, it would have a pH of 4.76.

Explanation:

correct me if I'm wrong ❤️

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zvonat [6]

Answer:

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Explanation:

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3 years ago

A sheet of gold weighing 8.8 g and at a temperature of 10.5°C is placed flat on a sheet of iron weighing 19.5 g and at a tempera

timofeeve [1]

Answer:

$T = 36.393\,^{\textdegree}C$

Explanation:

The contact between the sheet of gold and the sheet of iron allows a heat transfer until thermal equilibrium is done, which means that both sheets have the same temperature:

$-Q_{iron} = Q_{gold}$

$-(0.008\,kg)\cdot (452\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-54.4\,^{\textdegree}C) = (0.0195\,kg)\cdot (129\,\frac{J}{kg\cdot ^{\textdegree}C} )\cdot (T-10.5\,^{\textdegree}C)$

$-(3.616\,\frac{J}{^{\textdegree}C})\cdot (T-54.4\,^{\textdegree}C) = (2.515\,\frac{J}{^{\textdegree}C})\cdot (T-10.5^{\textdegree}C)$

$-1.438\cdot (T - 54.4^{\textdegree}C) = T-10.5^{\textdegree}C$

$-1.438\cdot T +78.227^{\textdegree}C = T - 10.5^{\textdegree}C$

$2.438\cdot T = 88.727\,^{\textdegree}C$

The final temperature is:

$T = 36.393\,^{\textdegree}C$

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