If time is specified, the distance may be estimated in constant acceleration using the formula: X=(at2)/2 if the beginning velocity is 0. (A automobile begins from a stop...) As a result, X=(6*10*10)/2=600/2 = 300 m.
Answer:
The speed of the plank is 81.68 m/s
Explanation:
Given that,
Speed of bullet = 152 m/s
Speed of wood = 128 m/s
Speed of another bullet = 97 m/s
We need to calculate the speed of plank
Using conservation of momentum
Where,
u = initial velocity
v = final velocity
....(I)
....(II)
From equation(I) and equation(II)
Hence, The speed of the plank is 81.68 m/s
Answer:
To summarize, an object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is...
Answer:
Half as much as it was
Explanation:
According to Charles law
PV = k
P is the pressure
V is the volume
If PV= k, then P1V1= P2V2
P1 and P2 are the initial and final pressure respectively
V1 and V2 are the initial and final volume respectively
Given
V1 =11.2litres
P1 = 0.860atm
If the volume is doubled, V2 = 2(11.2) = 22.4litres
Get P2
P2 = P1V1/V2
P2 = 0.860×11.2/22.4
P2 = 0.860/2
P2 = P1/2 (since P1 =0.860)
P2 = 1/2 P1
Hence the pressure becomes halved if the volume is doubled
Answer:
How far horizontally from point A does the ball hit the floor d= 5 m
Explanation:
By law of conservation of energy we can say that
final Kinetic energy kf+ final potential energy Uf= initial Kinetic energy ki+ initial potential energy Ui
We know that the ball has Uf, the ball at the bottom and no Ki ,the ball at initial state
therefore,
Kf= Ui
therefore,
MOI for Solid ball =
=
Now substituting the values to get value of V
V= 7.48 m/s
now to calculate How far horizontally from point A does the ball hit the floor
h=
2=
t=0.6385 sec
now horizontal distance d= vt = 0.6385×7.48= 5.00 m