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3 years ago

Knowing that a ball traveled 16 feet in one second, how much will it travel in the first quarter second?

Physics

2 answers:

Oksana_A [137]3 years ago

8 0

Answer:

4 Feet

Explanation:

Because A Quarter of 16 is 4

Ilya [14]3 years ago

4 0

You really can't tell. You don't know if its speed was constant for the whole second, or whether it was accelerated, decelerated, intermittent, bouncing back and forth, etc. All you know is that after 1 second, it had moved 16 ft.

IF its speed was constant AND it moved in a straight line, THEN it moved 4 ft in the first quarter of that second.

If it rolled off of a roof and FELL 16 ft in the first second, then it fell 1 foot in the first quarter second.

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Help me please i dont understand

alexandr402 [8]

Option A is the correct answer.

5 0

3 years ago

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

Nostrana [21]

Answer:

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

$E_1 = E_2$

Let the position where net field is zero will lie at distance "r" from q1

$\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}$

now we will have

$\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}$

now square root both sides

$\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}$

now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

8 0

3 years ago

ow long must a simple pendulum be if it is to make exactly ten swings per second? (That is, one complete vibration takes exactly

Igoryamba

The period T of a pendulum is given by:
$T=2 \pi \sqrt{ \frac{L}{g} }$
where L is the length of the pendulum while $g=9.81 m/s^2$ is the gravitational acceleration.

In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is $T=0.200 s$ . Using this data, we can solve the previous formula to find L:
$L=g ( \frac{T}{2\pi} )^2=(9.81 m/s^2)( \frac{0.2 s}{2 \pi} )^2=1 \cdot 10^{-3} m=1 mm$

4 0

3 years ago

When you break a magnet in half how many poles does each piece have.

Anastaziya [24]

It will have two poles

7 0

3 years ago

I Need help with this problem i don’t know what to do

Mazyrski [523]

Answer:

The density of the sample is 36 g/cm³

Explanation:

m= 972g

l=3cm

V = l³ = 3³ = 27 cm³

density = mass/volume

= 972/27

= 36 g/cm³

8 0

3 years ago