Answer:
38 kJ
Explanation:
The solution is obtained using the energy balance:
ΔE=E_in-E_out
U_2-U_1=Q_in+W_in-Q_out
U_2=U_1+Q_in+W_in-Q_out
=38 kJ
Answer:
The answer is 2217.32m³
Explanation:
Given that:
V₂ = (15 + 5/2) * 3 * 100 = 3000 m³
r₁ = 21.7kN/m3
w (water) = 11.4%.
e₂ (void ratio) = 0.47
V₁ = ?
Now,
rd₁ = r₁/1 + w₁ = 21.7/1 +(11.4/100)
= 19.47 kN/m3
Thus,
rd₂ = r₁/1 + e₂ = 21.7/1+ 0.47 = 14.76 kN/m3
Then,
V₁/V₂ = rd₁/ rd₂
V₁ = 3000 * 14.76/19.97
V₁ = 2217.32m³
Therefore, volume that should be excavated from the borrow pit is 2217.32m³
Answer:
See Explanation Below
Explanation:
The question is divided into three parts
1. Describe the factors that contribute to a disk drive’s average access time.
The answer to this is
a. Rotational Delay
b. Track-to-Track seek time or head movement
c. Head to head switching time
Each of the aforementioned factors affects the disk drive's average access time.
The rotational delay is the time between information requests and how long it takes the hard drive to move to the sector where the requested data is located
Track to track is the amount of time it takes the read/write head to search or seek between adjacent tracks
Head to head switching is an action taken by the hard drive head that moves the current action being performed on one read/write head to another
2. Which of these factors is improved if the spin rate is increased?
In the aforementioned factors, the rotational delay gets decreased when the spin rate gets increased.
3. Which is improved if areal density is increased?
The track to track seek time gets improved; the reason for this is that the the increment in the areal density makes the tracks to become narrowed and tightened together.
