Question

Consider the 65 N light fixture supported as in the figure. Find the tension in the supporting wires.

Answer 1

By using Lami's theorem formula, the tension in the supporting wires is 48.6 Newtons

TENSION

• Tension is also a force having Newton as S.I unit.

• The tension in the wire will be the same.

This question can be solved by using either vector diagram or by using  Lami's theorem.

The sum of two given angles  = 42 + 42 = 84 degrees

The third angle = 180 - 84 = 96 degrees.

Below is the Lami's theorem formula

$\frac{T}{sin\alpha } = \frac{T}{sin\beta } = \frac{W}{sinY}$

Where

$\alpha = \beta$ = 42 + 90 = 132 degrees

Y = 96 degrees

W = 65 N

By using the formula, we have

$\frac{T}{sin\alpha } = \frac{W}{sinY}$

T/sin 132 = 65/sin96

Cross multiply

T = 0.743 x 65.57

T = 48.56 N

Therefore, the tension in the supporting wires is 48.6 Newtons approximately.

Learn more about Tension here: brainly.com/question/24994188