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Advocard [28]
2 years ago
9

A section of a two-lane highway has 12-ft lanes and a design speed of 75 mi/h. The section contains a vertical curve and a horiz

ontal curve. The vertical curve connects a-2.5% grade and a 1.5% grade. The PVT of this vertical curve is at station 36 50. The PC of the horizontal curve is located 294 ft before the PVC of the vertical curve. The horizontal curve hassuperelevation of 8% and central angle of 38 degrees. If the vertical and horizontal curves are designed to meet the minimum required lengths for the given design speed, calculate the stations of the PC and PT.

Engineering
1 answer:
spayn [35]2 years ago
6 0

Answer:

Explanation: see attachment below

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The correct option is;

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Explanation:

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When the wear occurs at the outer edges of the tire, the load of the car rests on the outer edges as the contact patch increases due to the tire being under-inflated

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3 years ago
Read 2 more answers
A wastewater treatment plant has two primary clarifiers, each 20m in diameter with a 2-m side-water depth. the effluent weirs ar
jasenka [17]

Answer:

overflow rate 20.53 m^3/d/m^2

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Explanation:

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surface\  area =\frac{pi}{4}\times diameter ^2 = \frac{pi}{4}\times 20^2

surface area = 314.16 m^2

volume of tankV  = A\times side\ water\ depth

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Length\ of\  weir = \pi \times diameter of weir

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overflow rate =v_o = \frac{flow}{surface\ area} = \frac{6450}{314.16} = 20.53 m^3/d/m^2

Detention timet_d = \frac{volume}{flow} = \frac{628.32}{6450} \times 24 = 2.34 hr

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6 0
2 years ago
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