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Advocard [28]
3 years ago
9

A section of a two-lane highway has 12-ft lanes and a design speed of 75 mi/h. The section contains a vertical curve and a horiz

ontal curve. The vertical curve connects a-2.5% grade and a 1.5% grade. The PVT of this vertical curve is at station 36 50. The PC of the horizontal curve is located 294 ft before the PVC of the vertical curve. The horizontal curve hassuperelevation of 8% and central angle of 38 degrees. If the vertical and horizontal curves are designed to meet the minimum required lengths for the given design speed, calculate the stations of the PC and PT.

Engineering
1 answer:
spayn [35]3 years ago
6 0

Answer:

Explanation: see attachment below

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Now, suppose that you have a balanced stereo signal in which the left and right channels have the same voltage amplitude, 500 mV
eimsori [14]

Answer:

R₁ = 32kΩ

Explanation:

See attached image

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Explain why change is inevitable in complex systems and give examples (apart from prototyping and incremental delivery) of softw
Over [174]

Explanation:

The change in complex systems can be explained according to the relationship of the environment where the system is implemented.

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Which type of finish is absorbed into the wood?
stiks02 [169]
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1. Which of the following is the ideal way to apply pressure onto pedals?
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I think D. By pressing gradually
8 0
2 years ago
Read 2 more answers
A lake with constant volume 1.1 x 10^6 m^3 is fed by a stream with a non-conservative pollutant of 2.3 mg/L and flow rate 35 m^3
Jet001 [13]

Answer:

12.84 mg/L

Explanation:

We are given;

Volume of lake; V = 1.1 x 10^(6) m³

decay coefficient; K = 0.10/day = 0.1/(24 × 60 × 60) /s = 0.00000115741 /s

Factory rate: Q_f = 4.3 m³/s

Factory concentration: C_f = 100 mg/L

Stream rate: Q_s = 34 m³/s

Stream Concentration: C_s = 2.3 mg/L

Now, to find the steady state concentration of pollutant in the lake, we will use the formula;

(Q_s•C_s) + (Q_f•C_f) = (Q_f + Q_s)C_L + (KV•C_L)

Where C_L is the steady state concentration of pollutant in the lake.

Thus, making C_L the subject, we have;

C_L = [(Q_s•C_s) + (Q_f•C_f)]/(Q_f + Q_s + K•V)

Plugging in the relevant values gives;

C_L = ((34 × 2.3) + (4.3 × 100))/(4.3 + 34 + (0.00000115741 × 1.1 × 10^(6)))

C_L = 12.84 mg/L

4 0
3 years ago
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