A section of a two-lane highway has 12-ft lanes and a design speed of 75 mi/h. The section contains a vertical curve and a horiz
ontal curve. The vertical curve connects a-2.5% grade and a 1.5% grade. The PVT of this vertical curve is at station 36 50. The PC of the horizontal curve is located 294 ft before the PVC of the vertical curve. The horizontal curve hassuperelevation of 8% and central angle of 38 degrees. If the vertical and horizontal curves are designed to meet the minimum required lengths for the given design speed, calculate the stations of the PC and PT.
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Answer:
Do you mean 4m^3 and 3.0 tones?
Explanation:
solution:
Mass = m = 3.0 tones
- 1 ton = 1,000 kg
= 3.0 × 1,000
= 3,000 kg
volume = v = 4m^3
Required:
Mass density of oil = p = ?
We know that;
The answer is:
750kg / m^3