Answer:
V₂ = 530.5 mL
Explanation:
Given data:
Initial temperature = 20.0°C
Final temperature = 40.0 °C
Final volume = 585 mL
Initial volume = ?
Solution:
Initial temperature = 20.0°C (20+273 = 293 K)
Final temperature = 40.0 °C (40+273 = 323 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₁ = V₂T₁ /T₂
V₂ = 585 mL × 293 K / 323 K
V₂ = 171405 mL.K / 323 K
V₂ = 530.5 mL
Answer:
D
Explanation:
Glucose is made of 6 Carbon atoms, 12 Hydrogen atoms, and 6 Oxygen atoms.
The equation is: C6H12O6
Answer:
Equilibrium constant for is 0.5
Equilibrium constant for decomposition of is
Explanation:
dissociates as follows:
initial 0.72 mol 0 0
at eq. 0.72 - 0.40 0.40 0.40
Expression for the equilibrium constant is as follows:
Substitute the values in the above formula to calculate equilibrium constant as follows:
Therefore, equilibrium constant for is 0.5
Now calculate the equilibrium constant for decomposition of
It is given that is decomposed.
decomposes as follows:
initial 1.0 M 0 0
at eq. concentration of is:
Expression for equilibrium constant is as follows:
Substitute the values in the above expression
Equilibrium constant for decomposition of is
Answer:
8. A golf ball feels heavier than a table-tennis ball because a golf ball is denser; that is, it has more mass in a similar volume.
10.
The density of the unknown substance is 10.50 g/mL. According to the table, the substance that has the same amount of density is silver. Therefore, the unknown substance is silver.
Explanation:
I'll leave the rest to other people
When electrical power is applied to two plates placed inside the water, electrolysis occurs and hydrogen appear on the cathode and Oxygen on anode. It is due to the ideal faradaic efficiency, the amount of hydrogen generated is twice the number of moles of oxygen.
If you look at the equation , reduction occurs at cathode i.e
2 H+ + 2e−<span> → H</span>2
Oxidation occurs at anode
2 H2O → O2 + 4 H+ + 4e<span>−
</span>
Overall reaction
2 H2O(l) → 2 H2(g) + O2(g<span>)
Therefore, </span><span> volume of gas collected over one electrode double the volume of gas collected over the other electrode.</span>