Answer:
Number of moles of nitrogen produced from 167.7 g of sodium azide are 3.87.
Explanation:
Given data:
Mass of sodium azide = 167.7 g
Moles of nitrogen gas produced = ?
Solution:
First of all we will write the balance chemical equation of decomposition of sodium azide.
Chemical equation:
2NaN₃ → 3N₂ + 2Na
Number of moles of sodium azide:
Number of moles of sodium azide = mass / molar mass
Number of moles of sodium azide = 167.7 g/ 65 g/mol
Number of moles of sodium azide = 2.58 mol
Now we compare the moles of sodium azide with nitrogen from balance chemical equation.
NaN₃ : N₂
2 : 3
2.58 : 3/2×2.58 = 3.87
Number of moles of nitrogen produced from 167.7 g of sodium azide are 3.87.
Mass of nitrogen produced = moles × molar mass
Mass of nitrogen produced = 3.87 mol × 14 g/mol
Mass of nitrogen produced = 54.18 g.
Answer:
The correct answer is - 10400 years.
Explanation:
Half-life an element is the time required to decay the half amount of the initial amount of the element.
Here, the initial amount n(i) = 100 gm
remained amount n(r) = 25 gm
then n =?
The formula for the calculating initial amount
n(i)=n(r)⋅2^n
n(i)=n(r)⋅2^n
n(i)/n(r) =2^n
puting value,
100/25 = 2^n
2^n = 4
n = 2
so to decay this amount there is two half life cycles involved,
Thus, time = 2*5700
= 10400 years.
The statement that is true is that A molecule having a covalent bond may be polar or Nonpolar.
Answer:
805.6 moles
Explanation:
Molarity = 1.52mL
Volume = 530mL
1.52 moles is present in 1mL,
1mL = 0.001L
1.52 moles = 0.001L
X moles = 0.53L
X = (1.52 × 0.53) / 0.001
X = 805.6moles
805.6moles is present in 530mL or 0.52L
I'm pretty sure the answer is Temperature
