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iren2701 [21]
3 years ago
15

11. Examine the table provided. Which of the objects is producing

Physics
1 answer:
ivann1987 [24]3 years ago
3 0

Answer:

b is the answer tennis ball

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<em>velocity over time I think</em>

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A ball at rest rolls across a frictionless floor at 12.0 m/s/s. How far will it travel in
professor190 [17]

Answer:

The distance, d travelled by the ball is 768 metres.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Hence, if we subtract the final speed from the initial speed and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{initial \; speed  -  final \; speed}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is initial and final speed respectively, measured in ms^{-1}

t is time measured in seconds.

Given the following data;

Acceleration = 12.0m/s²

Time, t = 8secs

Velocity =?

First, we would calculate its velocity;

a = \frac{v  -  u}{t}

Since the ball rolls at rest, initial velocity is zero (0).

V = a * t

V = 12 * 8

Velocity = 96ms^{-1}

We can now solve for the distance;

Velocity = \frac{distance}{time}

Therefore,

Distance = velocity * time

Distance = 96 * 8

Distance = 768m.

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The illustration above depicts a spring being compressed and then released. Changes in both potential and kinetic energy occur d
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the potential energy is increasing through steps A & B, then decreases at C.

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Find the acceleration for a force of 2 N acting on 2 kg.
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The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.

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If the time between the horn sounding and the people on the ship hearing the echo from the ship is 4 seconds, how far away is th
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D

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