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jeka94
3 years ago
7

During the new moon phase, why is the Moon not visible in the sky?

Physics
1 answer:
katrin [286]3 years ago
4 0

Answer:

<em>During the new moon phase, the moon is not visible because Sometimes it can be detected by noting the visible absence of the stars that it blocks. Additionally, during the new moon, sometimes enough light is reflected off the surface of the Earth that the disk of the moon is faintly visible</em>

Explanation:

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A trolley has a mass of 1.2 kg and a speed of 4.5 m/s. The trolley crashes into a stationary trolley of mass 0.8 kg. On impact t
attashe74 [19]

(a) The momentum of the first trolley is 5.4 kgm/s

(b) The velocity of the trolleys after impact is 2.7m/s

<u>Explanation:</u>

Given:

Mass, m₁ = 1.2kg

Velocity, v₁ = 4.5m/s

Mass, m₂ = 0.8kg

v₂ = 0

(a) Momentum of the trolley before impact, p

We know:

Momentum = mass X velocity

p = 1.2 X 4.5

p = 5.4 kgm/s

Therefore, the momentum of the first trolley is 5.4 kgm/s

(b) Speed of the trolleys after impact, v = ?

During collision, the momentum is conserved.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

(1.2 X 4.5) + (0.8 X 0) = (1.2 +0.8) X v

5.4 + 0 = 2v

v = 2.7m/s

Therefore, the velocity of the trolleys after impact is 2.7m/s

8 0
3 years ago
Gravity is greater when there is
Papessa [141]
-- more mass involved

-- less distance between the two objects
4 0
3 years ago
Which moon has a thick atmosphere made mostly of nitrogen?
Delicious77 [7]
the answer is Titan
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7 0
3 years ago
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8 0
3 years ago
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A current of 3.6-A flows through a conductor. Calculate how much charge passed through and cross-section of the conductor in 25s
Anastaziya [24]

Answer:

90 C

Explanation:

Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,

I = dQ/dt

dQ = Idt

∫dQ = ∫Idt

Q = It................................ Equation 1

Where Q = amount of charge, I = current, t = time.

Given: I = 3.6 A, t = 25 s.

Substituting into equation 1,

Q = 3.6(25)

Q = 90 C.

Hence the amount of charge passing through the cross section of the conductor = 90 C

6 0
3 years ago
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