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Aliun [14]
3 years ago
14

The Johnson family pays $19.75 at the game for 3 ice cream cones and 4 funnel cakes. The Duke family pays $35.25 at the same gam

e for 5 ice cream cones and 8 funnel cakes. How much does a funnel cake cost? How much does an ice cream cone cost?
Mathematics
1 answer:
postnew [5]3 years ago
7 0

Answer:

$1.75  cost of the funnel cake and $4.25 cost of the ice cream cone.

Step-by-step explanation:

x = cost of the ice cone cone

y = cost of the funnel cake

3x + 4y = 19.75      multiply (-2)       ⇔     -6x - 8y = -39.50

5x + 8y = 35.25    do not change   ⇔  +<u>  5x + 8y = 35.25</u>

                                                                     -x  =  -4.25

                                                                      x = 4.25  cost of the ice cream cone

Substitute into the second equation x = 4.25 and solve  for y

5(4.25) + 8y = 35.25

21.25 + 8y = 35.25

  8y = 14

y = 1.75    cost of the funnel cake

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Using <u>complex numbers and radicals</u>, it is found that the correct option is C.

When a complex number is a root of a polynomial function, it's conjugate also has to be.

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The same is valid for radicals, as they are in the \pm format.

  • Since 7 - \sqrt{5} is a root, 7 + \sqrt{5} is also a root.

Hence, option C is correct.

For more on <u>complex numbers and radicals</u>, you can check brainly.com/question/25173944

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3 years ago
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Answer:

d_{AB}\ne d_{JK}

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Therefore,

Option (A) is false

Option (B) is false

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Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

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Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

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From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

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Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

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d_{GH}\:=\:3

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d_{AB}\ne d_{JK}

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Therefore,

Option (A) is false

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The weight of the full steel bead tire in pounds = 800 / 453.592 = 1.76

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