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Vaselesa [24]
3 years ago
12

How many kilograms of oseltamivir would be needed to treat all the people in a city with a population of 400000 people if each p

erson consumes two oseltamivir capsules a day for 5 days? Express your answer to one significant figures and include the appropriate units.
Chemistry
1 answer:
enyata [817]3 years ago
6 0

Answer:

300 kg

Explanation:

The give parameters obtained from a similar question are;

The mass of oseltamivir per capsule = 75 mg

The mass of oseltamivir required, <em>M</em>, is given as follows;

M = The mass of oseltamivir per capsule × The mass taken per person per day × 5 days × The number of people in the city

M = 0.75 mg/capsule × 2 capsule/(day·person) × 5 days × 400,000 people

M = 300,000,000 mg = 300 kg

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What is the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml?
Firdavs [7]

Answer: The final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock CuSO_4 solution = 2.5 M

V_1 = volume of stock CuSO_4solution = 5 ml  

M_1 = molarity of diluted CuSO_4 solution = ?

V_1 = volume of diluted CuSO_4 solution = 750 ml

Putting in the values we get:

2.5\times 5=M_2\times 750

M_2=0.017

Therefore the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

6 0
3 years ago
The normal freezing point of a certain liquid
stepladder [879]

Answer : The molal freezing point depression constant of X is 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of X liquid (solvent) = 450.0 g

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X= 0.4^oC

i = Van't Hoff factor = 1  (for non-electrolyte)

K_f = molal freezing point depression constant of X = ?

m = molality

Now put all the given values in this formula, we get

[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}

k_f=4.12^oC/m

Therefore, the molal freezing point depression constant of X is 4.12^oC/m

4 0
3 years ago
2 C2H6 + 7 026 H2O + 4 CO2
Kay [80]

Answer:

Oxygen is limiting reactant

Explanation:

Based on the chemical reaction:

2C2H6 + 7O2 → 6H2O + 4CO2

<em>2 mole of ethane reacts with 7 moles of oxygen</em>

<em />

For a complete reaction of 5.25 moles of ethane are required:

5.25 moles Ethane * (7mol Oxygen / 2mol Ethane) = 18.38 moles of oxygen

As there are just 15.0 moles of oxygen

<h3>Oxygen is limiting reactant</h3>
3 0
3 years ago
The first method of determining the chemical composition of substances in space was to
ehidna [41]
<span>The first method to determine the chemical composition of a substance in space was using light. By determining red shift in the observed spectrum of light they could determine the elements they were observing. Different elements change the way light behaves and from this scientists can determine the makeup of things such as stars and nebulas.</span>
5 0
3 years ago
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Carbon has two naturally occurring isotopes: C-12 (natural abundance is 98.93%) and C-13 (natural abundance is 1.07%). How many
Sav [38]
The number of atoms present, on average, will be the natural abundance of the isotope times the number of atoms in the sample => number of C-13 atoms = C-13 abundance * number of atoms in the sample = 1.07% * 30,000 = 1.07 * 30,000 / 100 = 321 atoms.<span> Answer: 321 atoms.</span>
5 0
3 years ago
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