Sinusoidal oscillator frequency of oscillation is given below.
Explanation:
The criterion for a stable oscillator is given in the equation
l A(jw)β(jw) l ≥ 1
In this task A represents the gain of the amplifier , and
β represents gain/attenuation of the second-order bandpass filter.
This sinusoidal oscillation is a special edge case where the product is equal to one.
So the condition is A-K=1
to obtain the sustained oscillations at the desired frequency of oscillations, the product of the voltage gain A and the feedback gain β must be one or greater than one. In this case, the amplifier gain A must be 3. Hence, to satisfy the product condition, feedback gain β must be 1/3.
Answer:
t=14ns
Explanation:
We make the relation between the specific access time and the memory percentage in each level, so


Average Access Time is 14 nsec.
Answer:
the elongation of the metal alloy is 21.998 mm
Explanation:
Given the data in the question;
K = σT/ (εT)ⁿ
given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,
strain-hardening exponent n = 0.22
we substitute
K = 345 / 
K = 815.8165 Mpa
next, we determine the true strain
(εT) = (σT/ K)^1/n
given that σT = 412 MPa
we substitute
(εT) = (412 / 815.8165 )^(1/0.22)
(εT) = 0.04481 mm
Now, we calculate the instantaneous length
= 
given that
= 480 mm
we substitute
=
× 
= 501.998 mm
Now we find the elongation;
Elongation = 
we substitute
Elongation = 501.998 mm - 480 mm
Elongation = 21.998 mm
Therefore, the elongation of the metal alloy is 21.998 mm
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Answer:
Output signal shape: square, from 0.1 to 230 MHz. Output power: -10 dBm (at a load of 50 Ohms).
Explanation: