The two ways you can use to make an informal survey are:
- make field observations
- interview people using informal unstructured techniques
<h3>What are informal surveys?</h3>
In informal surveys can be regarded as a type of survey that can be made by the researcher by going to the field themselves and this can be done by using different methods or ways.
For instance, the researcher can go out to interview people that can give the data that is needed about the research such as informally asking them questions, unstructured techniques can also be used to solve critical issues.
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Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation:
Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Explanation:
Given that;
Weight of soil r = 118 lb/ft³
stress parameter C = 250 lb/ft²
φ total = 29°
depth Z = 12 ft
The shear strength on a horizontal plane at a depth of 12ft
ζ = C + δtanφ
where δ = normal stress
normal stress δ = r × z = 118 × 12 = 1416
so
ζ = C + δtanφ
ζ = 250 + 1416(tan29°)
ζ = 250 + 1416(tan29°)
ζ = 250 + 784.9016
ζ = 1034.9015 lb/ft²
Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Answer:
82.62%
Explanation:
The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
![z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean\ and\ \sigma=standard\ deviation.\\\\Given \ that\ \mu=12V, \sigma=0.11V.\\\\For\ x11.85V:\\\\z=\frac{11.85-12}{0.11} =-1.36\\\\](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%20%5C%5C%5C%5Cwhere%5C%20x%3Draw%5C%20score%2C%5Cmu%3Dmean%5C%20and%5C%20%5Csigma%3Dstandard%5C%20deviation.%5C%5C%5C%5CGiven%20%5C%20that%5C%20%5Cmu%3D12V%2C%20%5Csigma%3D0.11V.%5C%5C%5C%5CFor%5C%20x%3C12.15V%3A%5C%5C%5C%5Cz%3D%5Cfrac%7B12.15-12%7D%7B0.11%7D%20%3D1.36%5C%5C%5C%5CFor%5C%20x%3E11.85V%3A%5C%5C%5C%5Cz%3D%5Cfrac%7B11.85-12%7D%7B0.11%7D%20%3D-1.36%5C%5C%5C%5C)
From the normal distribution table, P(11.85 < x < 12.15) = P(-1.36 < z < 1.36) = P(z < 1.36) - P(z < -1.36) = 0.9131-0.0869 = 0.8262 = 82.62%
The statement that best describes the lower vc-turbo engine compression ratios is that its generate an increased amount of power with the average fuel consumption.
<h3>
Vc-turbo engine</h3>
In the engine, lower temperatures allow to run more ignition timing advance which makes significantly more power than increasing the compression ratio in a turbo engine.
Hence, the turbo engines run lower static compression ratios to increase the amount of power they can reliable generate on pump gas.
Therefore, the statement that best describes the lower vc-turbo engine compression ratios is that its generate an increased amount of power with the average fuel consumption.
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